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Vladimir79 [104]
3 years ago
10

When a wave hits an object,energy from the wave is both absorbed and reflected off the object

Physics
1 answer:
poizon [28]3 years ago
5 0
I believe the statement is true. Have a good day.
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A spring-loaded gun can fire a projectile to a height h if it is fired straight up. if the same gun is pointed at an angle of 45
Naily [24]
When firing straight up:
v^2 = u^2 - 2gh, where v = final velocity = 0, u = initial velocity, g = gravitational acceleration, h = maximum height attained.

Then,
0 = u^2 - 2gh
u = Sqrt (2gh) ---- (1)

When firing at 45°,
Initial velocity, U = u Sin 45 = Sqrt (2gh)·Sin 45

Maximum height, H = U^2*(Sin Ф)^2/2g

substituting;
H = [Sqrt (2gh)·Sin 45]^2*(Sin 45)^2]/2g
H = [2gh*(Sin 45)^2*(Sin 45)^2]/2g
H = [h*(Sin 45)^4] = h/4

Therefore, maximum height when the gun fires at 45° is a quarter of maximum height when the gun fires vertically up.
6 0
3 years ago
If a golf ball is swinging on a pendulum on the planet mars (g=3.711 m/s²) and it takes 7 seconds to complete one oscillation, w
sertanlavr [38]
T = 2*pi*Sqrt (L/g)

T = Period = Time to complete one oscillation, L = Length of the pendulum, g = gravitational acceleration.

Then,

L = {T/(2*pi)}^2*g = {7/(2*pi)}^2*3.711 = 4.606 m
4 0
3 years ago
Which are dangerous places to put a flammable substance? Check all that apply.
Murrr4er [49]

Answer:

near a flame and a hot plate

Explanation:

7 0
3 years ago
2. A large pack of snow of mass m sits at the top of a trail at a ski resort. Friction keeps the snow pack in place, but when it
Aleks [24]

Answer:

tanΘ

Explanation:

Let gravitational acceleration be g. When the avalanche starts to occur, the gravity force that is parallel to the slope is the same as friction force.

Gravity force that is parallel to the slope can be written as:

G = mgsinΘ

The friction force is the product of normal force and coefficient:

F_f = N\mu

where normal force N is the gravity in the direction perpendicular to the slope

F_f = \mu mgcos\theta

As stated before, gravity force that is parallel to the slope is the same as friction force:

G = F_f

mgsin\theta = \mu mgcos\theta

\mu = sin\theta / cos\theta = tan\theta

8 0
3 years ago
The sun transfers energy to the earth by radiation at a rate of approximately 1.00 kW per square meter of surface.
Mashutka [201]

Answer:

1320336992.2512 m²

1320.33 kilometers or 509.79 miles

Explanation:

Energy transferred by the sun

W=0.24\times 1\times 10^3=240\ W/m^2

Energy required by the United States is 1\times 10^{19}\ J/yr (assumed)

Power

P=\frac{E}{t}\\\Rightarrow P=\frac{1\times 10^{19}}{365.25\times 24\times 3600}\\\Rightarrow P=316880878140.2895\ W

Area

A=\frac{P}{W}\\\Rightarrow A=\frac{316880878140.2895}{240}\\\Rightarrow A=132033699.2512\ m^2

Area of the solar collector would be 1320336992.2512 m²

Converting to km²

1\ m^2=\frac{1}{1000\times 1000}\ km^2

1320336992.2512\ m^2=1320336992.2512\times \frac{1}{1000\times 1000}\ km^2=1320.33\ km^2

Converting to mi²

1\ m^2=\frac{1}{1609.34\times 1609.34}\ mi^2

1320336992.2512\ m^2=1320336992.2512\times \frac{1}{1609.34\times 1609.34}\ mi^2=509.79\ mi^2

Each side of the square would be 1320.33 kilometers or 509.79 miles

4 0
3 years ago
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