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Ratling [72]
3 years ago
11

A meteor moving 468 km per minute traveling in a south-to-north direction passed near Earth in 2013. Does this statement describ

e the meteor’s speed or velocity?
explain why
Physics
1 answer:
Thepotemich [5.8K]3 years ago
3 0

Answer:

this statement describes meteor's velocity,

because velocity is a vector quantity which has both magnitude as well as a specific direction and here the meteor's direction is specified in the statement hence we conclude that this statement describes meteor's velocity as well as speed too.

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Equipotential surface A has a potential of 5650 V, while equipotential surface B has a potential of 7850 V. A particle has a mas
timurjin [86]

Answer:

0.247 J = 247 mJ

Explanation:

From the principle of conservation of energy, the workdone by the applied force, W = kinetic energy change + electric potential energy change.

So, W = ΔK + ΔU =1/2m(v₂² - v₁²) + q(V₂ - V₁) where m = mass of particle = 5.4 × 10⁻² kg, q = charge of particle = 5.10 × 10⁻⁵ C, v₁ = initial speed of particle = 2.00 m/s, v₂ = final speed of particle = 3.00 m/s, V₁ = potential at surface A = 5650 V, V₂ = potential at surface B = 7850 V.

So, W = ΔK + ΔU =1/2m(v₂² - v₁²) + q(V₂ - V₁)

          = 1/2 × 5.4 × 10⁻²kg × ((3m/s)² - (2 m/s)²) + 5.10 × 10⁻⁵ C(7850 - 5650)

          = 0.135 J + 0.11220 J

          = 0.2472 J

          ≅ 0.247 J = 247 mJ

5 0
3 years ago
The Sears Tower is nearly 400 m high. How long would it take a steel ball to reach the ground if dropped on the top? What will b
kipiarov [429]

Answers:

a) 9.035 s

b) -88.543 m/s

Explanation:

The described situation is related to vertical motion (especifically free fall) and the equations that will be useful are:

y=y_{o}+V_{o}t+\frac{1}{2}gt^{2} (1)  

V=V_{o}+gt (2)  

Where:  

y=0 is the final height of the steel ball

y_{o}=400 m is the initial height of the steel ball

V_{o}=0 is the initial velocity of the steel ball (it was dropped)

V is the final velocity of the steel ball

t is the time it takes to the steel ball to reach the ground

g=-9.8 m/s^{2} is the acceleration due to gravity

<u>Knowing this, let's begin with the answers:</u>

<h2>a) Time it takes the steel ball to reach the ground</h2>

We will use equation (1) with the conditions listed above:

0=y_{o}+\frac{1}{2}gt^{2} (3)  

Isolating t:

t=\sqrt{\frac{-2y_{o}}{g}} (4)  

t=\sqrt{\frac{-2(400 m)}{-9.8 m/s^{2}}} (5)  

t=9.035 s (6)  

<h2>b) Final velocity of the steel ball</h2>

We will use equation (2) with the conditions explained above and the calculaated time:

V=gt (7)  

V=(-9.8 m/s^{2})(9.035 s) (8)  

V=-88.543 m/s (9)  The negative sign indicates the direction of the velocity is downwards

3 0
3 years ago
Which object would have a LARGER gravitational force acting upon it? (assume the objects are at the same height above the Earth.
juin [17]
It would be D because there is more gravitational forces acting on it than a small block of wood 
3 0
3 years ago
Read 2 more answers
Look at this model of an atom. Using a periodic table, which element does it represent?
Elodia [21]

Answer:

Nitrogen

Explanation:

5 0
3 years ago
If you are inside a car and the car is struck by lightning, it is best to stay inside because the electric field inside the car
Contact [7]

Answer:

Get out if the car

Explanation:

Get out of the car because the car could explode by over eclectic power

5 0
3 years ago
Read 2 more answers
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