Answer:
1.4 m/s
Explanation:
The minimum speed will be when the diver's initial velocity is horizontal.
First, find the time it takes for the diver to fall 10 meters.
Given:
Δy = 10 m
v₀ᵧ = 0 m/s
aᵧ = 9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
10 m = (0 m/s) t + ½ (9.8 m/s²) t²
t = 1.43 s
Now find the initial horizontal velocity.
v = (2 m) / (1.43 s)
v = 1.4 m/s
Ernest Rutherford
don't know the age sorry
Answer:
He has a speed of 16.60m/s after 35.0 meters.
Explanation:
The final velocity can be determined by means of the equations for a Uniformly Accelerated Rectilinear Motion:
(1)
The acceleration can be found by means of Newton's second law:
Where
is the net force, m is the mass and a is the acceleration.
(2)
All the forces can be easily represented in a free body diagram, as it is shown below.
Forces in the x axis:
(3)
Forces in the y axis:
(4)
Solving for the forces in the x axis:

Where
and
:


Replacing in equation (2) it is gotten:






So the acceleration for the cyclist is
, now that the acceleration is known, equation (1) can be used:

However, since he was originally at rest its initial velocity will be zero (
).



He has a speed of 16.60m/s after 35.0 meters
Gravitational potential energy can be calculated using the formula:

Where:
PEgrav = Gravitational potential energy
m= mass
g = acceleration due to gravity
h = height
On Earth acceleration due to gravity is a constant 9.8 but since the scenario is on Mars, the pull of gravity is different. In this case, it is 3.7, so we will use that for g.
So put in what you know and solve for what you don't know.
m = 10kg
g = 3.7m/s^2
h = 1m
So we put that in and solve it.


The square root of 80 is: 8.944