The probability that a randomly selected customer will have to wait between 32 minutes and 37 minutes is 59.81%
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
Z score is given by:
z = (raw score - mean) / standard deviation
Given mean of 36 minutes and a standard deviation of 3 minutes.
For x = 32:
z = (32 - 36)/3 = -1.33
For x = 37:
z = (37 - 36)/3 = 0.33
P(-1.33 < z < 0.33) = P(z < 0.33) - P(z < -1.33) = 0.6179 - 0.0198 = 0.5981
The probability that a randomly selected customer will have to wait between 32 minutes and 37 minutes is 59.81%
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http://www.cpalms.org/Public/PreviewResourceAssessment/Preview/70464
Answer:
8.2+/-0.25
= ( 7.95, 8.45) years
the 95% confidence interval (a,b) = (7.95, 8.45) years
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean x = 8.2 years
Standard deviation r = 1.1 years
Number of samples n = 75
Confidence interval = 95%
z value(at 95% confidence) = 1.96
Substituting the values we have;
8.2+/-1.96(1.1/√75)
8.2+/-1.96(0.127017059221)
8.2+/-0.248953436074
8.2+/-0.25
= ( 7.95, 8.45)
Therefore the 95% confidence interval (a,b) = (7.95, 8.45) years
Answer:
Step-by-step explanation:
Slope = -6
Y-intercept (0, -4)
Answer: Lattice parameter, a = (4R)/(√3)
Step-by-step explanation:
The typical arrangement of atoms in a unit cell of BCC is shown in the first attachment.
The second attachment shows how to obtain the value of the diagonal of the base of the unit cell.
If the diagonal of the base of the unit cell = x
(a^2) + (a^2) = (x^2)
x = a(√2)
Then, diagonal across the unit cell (a cube) makes a right angled triangle with one side of the unit cell & the diagonal on the base of the unit cell.
Let the diagonal across the cube be y
Pythagoras theorem,
(a^2) + ((a(√2))^2) = (y^2)
(a^2) + 2(a^2) = (y^2) = 3(a^2)
y = a√3
But the diagonal through the cube = 4R (evident from the image in the first attachment)
y = 4R = a√3
a = (4R)/(√3)
QED!!!
