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d1i1m1o1n [39]
3 years ago
12

Simplify the function..........

Mathematics
1 answer:
andre [41]3 years ago
6 0
      7ab               a - b
--------------  -  --------------
a^2 - b^2            a + b

      7ab                 a - b
= --------------  -  --------------
  (a-b)(a+b)           a + b

      7ab                 (a - b)^2
= --------------  -  -----------------------
  (a-b)(a+b)           (a + b)(a-b)

      7ab                 a^2 - 2ab + b^2
= --------------  -  -----------------------
  (a-b)(a+b)           (a + b)(a-b)

      7ab - a^2 + 2ab -  b^2        
= -----------------------------------
                (a-b)(a+b)  

      - a^2 + 9ab -  b^2        
= -----------------------------------
                (a-b)(a+b)      

Answer is A. first one         
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DIA [1.3K]
1)
x^2 + (3y/2z) = 7
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2)
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3 years ago
Please help ! (only right answers please )!
Katen [24]

Answer:

c

Step-by-step explanation:

7 0
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I need help I can’t figure it out
dusya [7]

Answer:

\large\boxed{\dfrac{41p}{70q^4(r-9)^2}}

Step-by-step explanation:

\dfrac{2p^4}{5q^5(r-9)^3}\cdot\dfrac{41q(r-9)}{28p^3}\\\\=\dfrac{2\!\!\!\!\diagup^1\cdot41}{5\cdot28\!\!\!\!\!\diagup_{14}}\cdot\dfrac{q\!\!\!\!\diagup}{q^{5\!\!\!\!\diagup^4}}\cdot\dfrac{(r\!\!\!\!\!\!{--}-9)\!\!\!\!\!\!{--}}{(r-9)^{3\!\!\!\!\diagup^2}}\cdot\dfrac{p^{4\!\!\!\!\diagup}}{p^3\!\!\!\!\!\!\diagup}\\\\=\dfrac{41}{70}\cdot\dfrac{1}{q^4}\cdot\dfrac{1}{(r-9)^2}\cdot\dfrac{p}{1}\\\\=\dfrac{41p}{70q^4(r-9)^2}

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Katena32 [7]
<span>85 x 63 = 5355

hope it helps

---------------------</span>
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3 years ago
Read 2 more answers
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