Answer: -3/5, -1/2, -7/12, -6/11
The expression for (r-s)(x) is found by subtracting s from r. That difference is

. The expression for (r+s)(x) is found by adding them, which is

. Now we are told to evaluate (r*s)(x) which means they want us to multiply those and state the "new" expression that results.

. There you go!
Multiply these together: (7/26)*(6/15)*(5/14)*(4/13)
1.92% is the probability all friends order cotton sweatshirts but you can round that up to 2% C'=
Answer:
The correct option is (c).
Step-by-step explanation:
The complete question is:
The data for the student enrollment at a college in Southern California is:
Traditional Accelerated Total
Math-pathway Math-pathway
Female 1244 116 1360
Male 1054 54 1108
Total 2298 170 2468
We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the student is female. Which of the following pairs of probabilities is not a useful comparison?
a. 1360/2468 and 116/170
b. 170/2468 and 116/1360
c. 1360/2468 and 170/2468
Solution:
If two events <em>A</em> and <em>B</em> are independent then:

In this case we need to determine whether a student enrolled in an accelerated math pathway is independent of the student being a female.
Consider the following probabilities:

If the two events are independent then:
P (F|A) = P(F)
&
P (A|F) = P (A)
But what would not be a valid comparison is:
P (A) = P(F)
Thus, the correct option is (c).
F(x) = -3(x + 2)(x - 5)^3 > 0
(x + 2)(x - 5) > 0
x + 2 > 0 or x - 5 < 0
x > -2 or x < 5
-2 < x < 5
Therefore, the stated interval is false.