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Fantom [35]
2 years ago
6

A 1 newton force will stretch a spring 1 meter. The spring/mass system is damped by a force that is 8 times the instantaneous ve

locity. A 16 kg mass is attached to the spring. The spring is compressed 0.6 meters above the equilibrium position and given an initial downward velocity of 2 m/s. Determine the equation of motion of the mass
Mathematics
1 answer:
sukhopar [10]2 years ago
5 0

Answer:

Step-by-step explanation:

Given the mass is m =16kg, and 1N force will stretch the spring 1 m.

That is, F =1N,Z =1m. Now find the spring constant k:

F = kL = 1 = k(1) = k= 1N/m.

The damping force is 8times the instantaneous velocity, this means β = 8,

and the external force is f(t) = 0

Initially the object compressed 0.6m above equilibrium position,

with the downward velocity is 2m/s.

The differential equation for a spring mass system with

damping force and extemal force is: mx" + βxt + kx = f(t).

so, 16x"+ 8x' + x= 0, x(0} = -0.6, x'(0)= 2m/s.

Now solve the DE:

The auxilary equation for the homogeneous equation is 16x"+8x'+x=0

solving we get, 16r² + 8r + 1 = 0 => (4r + 1)² = 0 => r = - 1/4.

Then the general solution for the homogenous system is: x(t)=c_1e^{-t/4} +c_2te^{-t\4}.

Use the initial conditions x (0) = -0.6, x'(0) = 2m/s:

x(0)=c_1e^{0} +c_2(0)e^{0}=-0.6=c_1\\x'(t)=-\frac{1}{4}c_1e^{-t/4}+c_2e^{-t/4}-\frac{1}{4}c_2te^{-t/4}\\x'(0)=-\frac{1}{4}c_1e^0+c_2e^0-\frac{1}{4}c_2(0)e^0=2=-\frac{1}{4}(-0.6)+c_2=c_2=1.85.

Hence, x(t) =-0.6e^{-t/4}+1.85te^{-t/4}.

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Sunny_sXe [5.5K]
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\bf \qquad 
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7 0
2 years ago
Simplify cos^-1 (sqrt 3/2)<br><br> A. 60° <br> B. 30° <br> C. 240° <br> D. 150°
Fantom [35]
B.) 30 degrees would be correct here
7 0
3 years ago
What is an equation of the line that passes through the point
grin007 [14]

Answer:

y = 5x + 8

Step-by-step explanation:

If you want to find a equation parallel to the line given, you need to know the slope of the line given. Remember that parallel lines have the same slope.

5x - y = 4 and solving for y:

-y = -5x + 4 and solving for positive y:

y = 5x - 4

So the slope of that line is 5. We will use that along with the coordinate given to us to write the equation first in point-slope form then in slope-intercept:

y - (-2) = 5(x - (-2)) and

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y + 2 = 5x + 10 so

y = 5x + 8

8 0
3 years ago
Evaluate the expression for x=5 and y= 3
kenny6666 [7]

I will use the positive / negative property of the absolute value to split the equation into two cases, and I will use the fact that the "minus" sign in the negative case indicates "the opposite sign", not "a negative number".

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Whatever the value of x might be, taking the absolute value of x makes it positive. Since x might originally have been positive and might originally have been negative, I must acknowledge this fact when I remove the absolute-value bars. I do this by splitting the equation into two cases. For this exercise, these cases are as follows:

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5 0
3 years ago
4/5 as a decimal and How did you decide when you have calculated enough decimal places?
olga2289 [7]
Make 4/5 into 8/10 which would make the decimal .8.
4 0
3 years ago
Read 2 more answers
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