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Nana76 [90]
3 years ago
13

Write an expression using scale factor, k, for each dimension? 1D 2D 3D

Mathematics
1 answer:
melomori [17]3 years ago
8 0
The correct answer is1D k 2D k 3Dk
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the angle of elevation from point A to the top of the press box is 49 digree. if point A is 400ft from the base of press box, ho
Diano4ka-milaya [45]

Answer:

Press box is 460.15 feet high.

Step-by-step explanation:

From the picture attached,

Point A is 400 feet away from the press box.

Angle of elevation of point C is 49°.

By applying tangent rule in the given right triangle,

tan(49°) = \frac{\text{Opposite side}}{\text{Adjacent side}}

tan(49°) = \frac{BC}{AB}

BC = ABtan(49°)

BC = 400[tan(49°)]

BC = 460.15 ft

Therefore, press box is 460.15 feet high.

8 0
3 years ago
A planter is shaped like a regular hexagon. The side lengths are 2 meters and the apothem is 1.72 m. What is the area of the hex
lyudmila [28]

The area of the hexagonal planter is 10.32 m²

<h3>Regular hexagon</h3>

Regular hexagon are polygon with 6 sides and are equiangular. This means the angles are the same.

area of hexagon = 1 / 2 × apothem × perimeter of hexagon

apothem = 1.72 m

side length = 2 m

area of hexagon = 1 / 2 ×  1.72 × 6(2)

area of hexagon = 1 / 2 ×  1.72 × 12

area of hexagon = 20.64 / 2

area of hexagon = 10.32

area of hexagon = 10.32 m²

learn more on hexagon here: brainly.com/question/358118?referrer=searchResults

5 0
2 years ago
The measure of ∠1 =<br><br> 43<br> 86<br> 274
german

Answer:

m

Step-by-step explanation:

we know that

The inscribed angle measures half that of the arc comprising

so

m

m

m


8 0
4 years ago
Read 2 more answers
If DE = 37 cm and EF = 16 cm, then what are the possible lengths for DF so that DE,EF, and DF can form a triangle? Explain your
notsponge [240]

Answer:

The length of DF must be between 21 and 53.

Step-by-step explanation:

In a triangle, the length of two sides added together must exceed the length of the 3rd side. So, since EF is the shortest of the two givens, we know that EF + DF must be greater than DE. So we can plug in these numbers to find the minimum.

EF + DF > DE

16 + DF > 37

DF > 21

Now, for the upper maximum, we know that the two given lengths must be greater than the length of DF. So again, we can solve for the maximum using the amounts.

DE + EF > DF

37 + 16 > DF

53 > DF

With these two in mind, we know that DF must be between 21 and 53

8 0
3 years ago
A pharmaceutical company receives large shipments of aspirin tablets. The acceptance sampling plan is to randomly select and tes
VARVARA [1.3K]

Answer:

The probability that the whole shipment will be​ accepted is 0.5862.

Step-by-step explanation:

Let <em>X</em> = number of the aspirin tablets that doesn't meet the required specifications.

The probability of the random variable <em>X</em> is, P (X) = <em>p</em> = 0.03.

The sample of <em>n</em> = 47 tablets are tested from each batch.

The probability of any of the tablets being defective is independent of the others.

The probability mass function of <em>X</em> is,

P(X=x)={n\choose x}p^{x}(1-)^{n-x};\ x=0,1,2,3...

Compute the probability that the whole shipment of 3000 tablets will be​ accepted as follows:

P (X ≤ 1) = P (X = 0) + P (X = 1)

             ={47\choose 0}0.03^{0}(1-0.03)^{47-0}+{47\choose 1}0.03^{1}(1-0.03)^{47-1}\\=0.2389+0.3473\\=0.5862

Thus, the probability that the whole shipment will be​ accepted is 0.5862.

The sample of 47 tablets is significantly small when drawn from a population of 3000 tablets. So it is difficult to make conclusion about all such shipments of aspirin tablets.

5 0
3 years ago
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