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9966 [12]
3 years ago
6

Find the y-intercept of the line below.

Mathematics
1 answer:
ANEK [815]3 years ago
8 0
Y=mx+b, the b is your y-intercept so just rearrange your equation
y=(3/7)x+(2/7)
your y-intercept would be b) (2/7)
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i know but yes i need to know it

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3 years ago
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A farmer needs to ship 71 pumpkins to a grocery store if each crates can hold 19 pumpkins how many crates Will the farmer need ?
Lesechka [4]

Answer:

The farmer will need 7 crates.

Step-by-step explanation:

<em>It is given that there are 71 pumpkins in total.</em>

<em>And each crate holds 19 pumpkins.</em>

Let the number of crates required be<em> "n".</em>

The total number of pumpkins can be calculated by multiplying number of pumpkins in each crate with total number of crates.

Thus, the equation is

19(n) = 71

n = \frac{71}{19} = 7

Thus, the farmer needs 7 crates to hold total of 71 pumpkins.

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3 years ago
Urve revolves around the x-axis. if you cannot evaluate the integral exactly, use your calculator to approximate it. (round your
Archy [21]

The value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

Given the equation y=16-x^{2} and the limit of the integral be x=-1,x=1.

We are required to find the value of integration of y=16-x^{2} from x=-1 to x=1.

Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.

Integration is basically opposite of differentiation.

y=16-x^{2}

Find the integration of 16-x^{2}.

=16x-x^{3}/3

Now find the value of integration from x=-1 to x=1.

=16(1)-(1)^{3}/3-16(-1)-(-1)^{3}/3

=16(1)-1/3+16-1/3

=32-2/3

=(96-2)/3

=94/3

Hence the value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

Learn more about integration at brainly.com/question/27419605

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4 0
1 year ago
Add [ -6 -2 2] + [-3 2 1]
Troyanec [42]
-6 (negative six) is the answer
8 0
3 years ago
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Kara did a survey to determine to study the types of pets that students in her school had. She surveyed 300 students and found t
julsineya [31]

Answer:

(C)81

Step-by-step explanation:

Total Number of Students =300

Percentage who had cats, n(C) = 40%

Percentage who had both cats and dogs , n(C \cap D) = 12%

Percentage who had neither cats nor dogs, n(C \cup D)' =45%

Now:

Universal Set, U = n(C)+n(D)-n(C \cap D)+n(C \cup D)'

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Therefore:

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=81

3 0
3 years ago
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