1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
marishachu [46]
3 years ago
9

There's 4.1*10^25 particles of calcium phosphate, how many grams of calcium phosphate is that

Chemistry
1 answer:
Readme [11.4K]3 years ago
7 0

Mass of Calcium phosphate : = 21127.7 g

<h3>Further explanation</h3>

Given

4.1 x 10²⁵ particles of Calcium phosphate

Required

mass

Solution

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

mol Calcium phosphate :

n = N : No

n = 4.1 x 10²⁵ : 6.02 x 10²³

n = 68.11

mass Calcium phosphate Ca3(PO4)2 :

= mol x MW

= 68.11 x 310.2 g/mol

= 21127.7 g

= 21.13 kg

You might be interested in
How many half-lives are required for the concentration of reactant to decrease to 1.56% of its original value?4247.56.56
neonofarm [45]

Answer:

6 half-lives are required for the concentration of reactant to decrease to 1.56% of its original value.

Explanation:

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given:

Concentration is decreased to 1.56 % which means that 0.0156 of [A_0] is decomposed. So,

\frac {[A_t]}{[A_0]} = 0.0156

Thus,

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.0156=e^{-k\times t}

kt = 4.1604

The expression for the half life is:-

Half life = 15.0 hours

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

\frac{4.1604}{t}=\frac {ln\ 2}{t_{1/2}}

t = 6\times t_{1/2}

<u>6 half-lives are required for the concentration of reactant to decrease to 1.56% of its original value.</u>

6 0
4 years ago
Glucozo công thức phân tử
olganol [36]

Answer:I would copy and past but that’s a lot of work just read it

Explanation:

3 0
3 years ago
HELP ASAP 30 POINTS
allsm [11]

Answer:

Explanation:

Dind out

5 0
3 years ago
Read 2 more answers
13. A gas occupies 4.31 liters at a pressure of 0.755 atm. Determine the volume if the
wariber [46]

Answer:

13. 2.60 L.

14. 2.40 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and T are constant, and have different values of P and V:

(P₁V₁) = (P₂V₂)

<em>13. A gas occupies 4.31 liters at a pressure of 0.755 atm. Determine the volume if the  pressure  is increased to 1.25 atm.</em>

P₁ = 0.755 atm, V₁ = 4.31 L.

P₂= 1.25 atm, V₂ = ??? L.

∴ V₂ = (P₁V₁)/(P₂) = (0.755 atm)(4.31 L)/(1.25 atm) = 2.60 L.

<em>14. 600.0 mL of a gas is at a pressure of 8.00 atm. What is the volume of the gas at 2.00  at m.</em>

P₁ = 8.0 atm, V₁ = 600.0 mL.

P₂= 2.0 atm, V₂ = ??? L.

∴ V₂ = (P₁V₁)/(P₂) = (8.0 atm)(600.0 mL)/(2.0 atm) = 2400/0 mL = 2.40 L.

3 0
3 years ago
In a mixture of gases exerting a total pressure of 2.50 atm, carbon dioxide has a mole fraction of 0.450. What is the partial pr
AlladinOne [14]

Answer:

1.12 atm is the correct answer

3 0
3 years ago
Other questions:
  • What is liquid nitrogen
    13·2 answers
  • Can someone please do this for me
    14·1 answer
  • From the periodic table, the number of valence electrons for most of the main group elements may be determined directly from the
    6·1 answer
  • V1 = l; P1=40Pa; P2= 100 kpa; V2= 1.0 L please help!
    10·1 answer
  • The mass of an object is measured to be 55.6 g. Its volume is measured to be 48.5 mL.
    15·1 answer
  • A mixture containing initially 3.90 mole of NO(g) and 0.88 mole of CO2(g) was allowed to react in a flask of volume 1.00 L at a
    5·1 answer
  • How many moles of KOH are there in 27.5 mL of 0.250 M KOH?
    15·1 answer
  • The diagram below represents the organizational levels of living things.
    6·2 answers
  • In a victor Mayer's experiment 0.33g of organic liquid of molecular weight 120g/mol was vaporized at 293k and 1.013 *10 N/ m cal
    7·1 answer
  • Give two characteristics of liquid state<br>​
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!