How many moles of ethyl alcohol, C2H6O, are in a 16.0 g sample

Benzene and alkyl-substituted benzenes can be hydroxylated by reaction with H2O2 in the presence of an acidic catalyst. What is

Yuri [45]

Answer:

The electrophile is the hydroxide free radical

Explanation:

The hydroxylation of benzene and benzene derivatives using hydrogen peroxide proceeds in the presence of an acidic catalyst. The electrophile in this reaction is the hydroxyl free radical generated in an initial step of the reaction.

This is actually a free radical reaction. The hydroxyl radical previously generated reacts with the benzene ring to yield a radical that undergoes further rearrangement to yield the product phenol. The intermediate, shown as part of this reaction mechanism (refer to image attached) is a specie in which the odd electron is delocalized over the entire benzene ring. Loss of a proton completes the reaction mechanism yielding the corresponding phenol.

5 0

4 years ago

There are 24 hours in a day, 60 minutes in an hour, 7 days in a week, and 4 weeks in a month? using these conversions how many m

Serggg [28]

Explanation:

From your information above, assume 1 month is 28 days

1 days=24hours ; 28 days=672 hours (just multiply 1 days with 28)

1 hour=60minutes ; 672 hours=40,320 minutes

.. 1 month=40,320 minutes

5 0

2 years ago

A student mixes four reagents together, thinking that the solutions will neutralize each other. The solutions mixed together are

vaieri [72.5K]

Answer: Resulting solution will not be neutral because the moles of $OH^-$ ions is greater. The remaining concentration of $[OH^-]$ ions =0.0058 M.

Explanation:

Given,

[HCl]=0.100 M

$[HNO_3]$ = 0.200 M

$[Ca(OH)_2]$ =0.0100 M

[RbOH] =0.100 M

Few steps are involved:

Step 1: Calculating the total moles of $H^+$ ion from both the acids

moles of $H^+$ in HCl

$HCl\rightarrow {H^+}+Cl^-$

if 1 L of $HCl$ solution =0.100 moles of HCl

then 0.05L of HCl solution= 0.05 $\times$ 0.1 moles= 0.005 moles (1L=1000mL)

moles of $H^+$ in HCl = 0.005 moles

Similarliy

moles of $H^+$ in $HNO_3$

$HNO_3\rightarrow H^++NO_3^-}$

If 1L of $HNO_3$ solution= 0.200 moles

Then 0.1L of $HNO_3$ solution= 0.1 $\times$ 0.200 moles= 0.02 moles

moles of $H^+$ in $HNO_3$ =0.02 moles

so, Total moles of $H^+$ ions = 0.005+0.02= 0.025 moles .....(1)

Step 2: Calculating the total moles of $[OH^-]$ ion from both the bases

Moles of $OH^-\text{ in }Ca(OH)_2$

$Ca(OH)_2\rightarrow Ca^2{+}+2OH^-$

1 L of $Ca(OH)_2$ = 0.0100 moles

Then in 0.5 L $Ca(OH)_2$ solution = 0.5 $\times$ 0.0100 moles = 0.005 moles

$Ca(OH)_2$ produces two moles of $OH^-$ ions

moles of $OH^-$ = 0.005 $\times$ 2= 0.01 moles

Moles of $OH^-$ in $RbOH$

$RbOH\rightarrow Rb^++OH^-$

1 L of RbOH= 0.100 moles

then 0.2 [RbOH] solution= 0.2 $\times$ 0.100 moles = 0.02 moles

Moles of $OH^-$ = 0.02 moles

so,Total moles of $OH^-$ ions = 0.01 + 0.02=0.030 moles ....(2)

Step 3: Comparing the moles of both $H^+\text{ and }OH^-$ ions

One mole of $H^+$ ions will combine with one mole of $OH^-$ ions, so

Total moles of $H^+$ ions = 0.005+0.02= 0.025 moles....(1)

Total moles of $OH^-$ ions = 0.01 + 0.02=0.030 moles.....(2)

For a solution to be neutral, we have

Total moles of $H^+$ ions = total moles of $OH^-$ ions

0.025 moles $H^+$ will neutralize the 0.025 moles of $OH^-$

Moles of $OH^-$ ions is in excess (from 1 and 2)

The remaining moles of $OH^-$ will be = 0.030 - 0.025 = 0.005 moles

So,The resulting solution will not be neutral.

Remaining Concentration of $OH^-$ ions = $\frac{\text{Moles remaining}}{\text{Total volume}}$

$[OH^-]=\frac{0.005}{0.85}=0.0058M$

6 0

4 years ago

One electron in an atom has the quantum number set (3, 1, 0, ½), and another electron in the same atom has the quantum number se

guapka [62]

There are four quantum numbers that describe the placement of electrons in an atom's electron cloud: principal quantum number (n), angular quantum number (l), magnetic quantum number (ml) and electron spin number (ms). When presented, they are written as (n, l, ml, ms).

From the given set, they have same n and l quantum numbers. The n represents the shell, the l as subshell, ml is the orientation in space and ms is the direction of the spin. Therefore, these two electrons of the atom share a subshell but differ in the shape of the orbital only.

3 0

4 years ago

What is the heaviest noble gas? A.Helium B.Radon C.Fluorine D.Astatine

Ira Lisetskai [31]

Answer:

Radon is the heaviest Noble Gas

Explanation:

This statement is very easy to be solved. As we know that Noble Gases are group of Elements which have complete valence shell and are stable elements and don't react easily and hence, are found in mono-atomic form in nature. These elements can be found on the extreme right of the periodic table in group 8 or group 18. Following are the Noble elements,

(i) Helium

(ii) Neon

(iii) Argon

(iv) Xenon

(v) Radon

Now,

In statement we are provided with only two noble gases i.e. Helium and Radon. Therefore, it is easy among them to finalize the heaviest one as Radon having atomic mass of 222.02 g/mol and atomic radii of 0.22 nm is much denser/heavier than Helium having atomic mass of 4.0 g/mol and atomic radii of 0.122 nm.

5 0

3 years ago