Question

The second-order rate constant for the dimerization of a protein (P) P + P → P2 is 6.2 × 10−3/M · s at 25°C. Part 1 out of 2 If the concentration of the protein is 1.6 × 10−4 M, calculate the initial rate (M/s) of formation of P2. rate = × 10 M/s (Enter your answer in scientific notation.)

Answer 1

Answer:

$r=1.59\times 10^{-10}\ M/s$

Explanation:

According to the law of mass action:-

The rate of the reaction is directly proportional to the active concentration of the reactant which each are raised to the experimentally determined coefficients which are known as orders. The rate is determined by the slowest step in the reaction mechanics.

Order of in the mass action law is the coefficient which is raised to the active concentration of the reactants. It is experimentally determined and can be zero, positive negative or fractional.

The order of the whole reaction is the sum of the order of each reactant which is raised to its power in the rate law.

From the reaction given that:-

$P+P\rightarrown P_2$

The expression for the rate is:-

$r=k[P]^2$

Given that;- k= $6.2\times 10^{-3}$ /Ms

[P] = $1.6\times 10^{-4}$ M

Thus,

$r=6.2\times \:10^{-3}\times \:\left(1.6\times \:\:10^{-4}\right)^2\ M/s=1.59\times 10^{-10}\ M/s$