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3 years ago

If an unknown substance CANNOT be broken down into simpler substances, it is

Chemistry

2 answers:

Fynjy0 [20]3 years ago

7 0

If an unknown substance CANNOT be broken down into simpler substances, it is AN ELEMENT made of one kind of atom.

7nadin3 [17]3 years ago

3 0

Answer:

element

Explanation:

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Determine the number of atoms in 5.88 moles sodium.

ozzi

1 mole ------------ 6.02x10²³ atoms
5.88 moles ---- ?

atoms = 5.88 * 6.02x10²³ / 1

= 3.539x10²⁴ atoms

hope this helps!

4 0

3 years ago

The density of water is 1.0 grams per milliliter. What can you conclude from this simulation about whether an object will

aliina [53]

The density of water is 1.0 grams per milliliter then it will be sink in water

Density is a word we use to describe how much space an object or substance takes up in the volume and in relation to the amount of matter in that object or substance its mass) and another way to put it is that density is the amount of mass per unit of volume

Here given density is 1.0 grams per milliliter and it will be sink in water because the density of water in 1.0 g/ml and this object is more dense than water and the density of an object determines whether it will float or sink in another substance and an object will float if it is less dense than the liquid it is placed in and an object will sink if it is more dense than the liquid it is placed

Know more about density

brainly.com/question/18366165

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4 0

1 year ago

____ Na +____ I2 -----> ____ NaI

astraxan [27]

2Na + I2 —> 2NaI

No. of mol of 4.0g I2 = 4/(35.5x2) = 0.0563

No. of mol of NaI = 2 x 0.0563 = 0.113

No. of molecules of NaI = 0.113 x 6.02 x 10^23 = 6.78 x 10^22

7 0

4 years ago

When 231. mg of a certain molecular compound X are dissolved in 65. g of benzene (CH), the freezing point of the solution is mea

Elan Coil [88]

Answer:

Molar mass X = 18.2 g/mol

Explanation:

Step 1: Data given

Mass of compound X = 231 mg = 0.231 grams

Mass of benzene = 65.0 grams

The freezing point of the solution is measured to be 4.5 °C.

Freezing point of pure benzene = 5.5 °C

The freezing point constant for benzene is 5.12 °C/m

Step 2: Calculate molality

ΔT = i*Kf*m

⇒ΔT = the freezing point depression = 5.5 °C - 4.5 °C = 1.0 °C

⇒i = the Van't hoff factor = 1

⇒Kf = the freezing point depression constant for benzene = 5.12 °C/m

⇒m = the molality = moles X / mass benzene

m = 1.0 / 5.12 °C/m

m = 0.1953 molal

Step 3: Calculate moles X

Moles X = molality * mass benzene

Moles X = 0.1953 molal * 0.065 kg

Moles X = 0.0127 moles

Step 4: Calculate molar mass X

Molar mass X = mass / moles

Molar mass X = 0.231 grams / 0.0127 moles

Molar mass X = 18.2 g/mol

5 0

3 years ago

When the alkene below is brominated with NBS reaction can occur at more than one carbon.

katrin2010 [14]

Answer:

Four products are possible.(in attachment)

2,3,4,5 carbons attached to the bromine.

Explanation:

NBS is N-bromosuccinamide which is used to brominate the allylic and benzylic positions of the compound.

Mainly used for the allylic bromination Here, four products are possible among them two are formed by the direct allylic bromination and remaining two products are formed by the rearrangement of the radical formation.

2,3,4,5 carbons of the compound are attached to the bromine.

7 0

4 years ago