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NeX [460]
1 year ago
6

What would be the immediate product of neutron absorption by Ag 107

Chemistry
1 answer:
Novosadov [1.4K]1 year ago
4 0

The immediate product of neutron absorption by Ag-107 is silver atom with a mass of 108, Ag-108.

<h3>What is radioactivity?</h3>

Radioactivity is the spontaneous emission of radiation as wall as particles and energy l by the nucleus of elements due to their disintegration.

The radioactive particles that are usually emitted include:

  • alpha particles
  • beta particles and
  • neutrons

The neutron has a mass of 1.

When silver isotope having a mass of 107 absorbs a neutron, the silver isotope produces will have a mass of 108, Ag-108.

Learn more about radioactivity at: brainly.com/question/25750315

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What is the molar mass of an unknown gas<br> with a density of 4.95 g/L at 1.00 atm and<br> 25.0 °C?
mestny [16]

Answer:

121 g/mol

Explanation:

To find the molar mass, you first need to calculate the number of moles. For this, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = constant (0.0821 L*atm/mol*K)

-----> T = temperature (K)

Because density is comparing the mass per 1 liter, I am assuming that the system has a volume of 1 L. Before you can plug the given values into the equation, you first need to convert Celsius to Kelvin.

P = 1.00 atm                         R = 0.0821 L*atm/mol*K

V = 1.00 L                             T = 25.0. °C + 273.15 = 298.15 K

n = ? moles

PV = nRT

(1.00 atm)(1.00L) = n(0.0821 L*atm/mol*K)(298.15 K)

1.00 = n(0.0821 L*atm/mol*K)(298.15 K)

1.00 = (24.478115)n

0.0409 = n

Now, we need to find the molar mass using the number of moles per liter (calculated) and the density.

0.0409 moles           ? grams           4.95 grams
----------------------  x  ------------------  =   ------------------
        1 L                       1 mole                     1 L

? g/mol = 121 g/mol

**note: I am not 100% confident on this answer

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1.1   moles   of C10H8  is the  limiting  reagent  in   the  reaction between   reaction  C10H8   and   O2
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C10H8  is  the  limiting   reagent   since   1.1  moles  of  C10H8  is  totally   consumed   during  the  reaction
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