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nydimaria [60]
3 years ago
15

Which pair of expressions is equivalent?​

Mathematics
1 answer:
zalisa [80]3 years ago
4 0

Answer:

C is equivalent

Step-by-step explanation:

7/12*4/5

7*4/12*5

28/60

7/15

7/12/5/4

7/12*4/5

7*4/12*5

28/60

7/15

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1. Select all the triangles that can be rotated to match up with Triangle 1. Triangle 1 A B D C С​
emmasim [6.3K]

Answer:it should be B and D

Step-by-step explanation:

B could be rotated clockwise and D could be rotated clockwise as well.

8 0
4 years ago
One number is 8 greater than another. The product of the numbers is 84. Find the numbers.
mario62 [17]

Let x,y be the two numbers.

Given that one number is 8 greater than another.

Let x be the smaller number ans y be the greater number.

That is y=x+8. Let this be the first equation.

And also given that product of the two numbers is 84.

That is x × y = 84, let us plugin y=x+8 here.

x × (x+8) = 84

x²+ 8x -84 = 0.

x²+12x-4x-84 = 0

x(x+12)-4(x+12) =0

(x-4)(x+12)=0

That is x= 4 or -12.

<h3>If x=4 , y= 4+ 8 = 12</h3>

<h3>If x= -12, y= -12+8 = -4 </h3>

Hence two positive numbers corresponding to given conditions are 4,12.

And two negative numbers corresponding to given conditions are -12,-4.

Step-by-step explanation:

hope it may help you!!

please mark as brainlist please (´;︵;`)

5 0
4 years ago
Please solve all i will mark brainliest and 15 points.​
OleMash [197]

Answer:

Hope that will help you get

3 0
3 years ago
A person borrows $50000 loan from bank at a rate of 10% for 5 years compounded yearly.
Hatshy [7]
<h3>Given:</h3>
  • P= $50,000
  • R= 10%
  • T= 5 years
<h3>Note that:</h3>
  • P= Principal amount
  • R= Rate of interest
  • T= Time period
<h3>Solution:</h3>

\large\boxed{Formula: A= P(1+ \frac{R}{100}{)}^{T}}

Let's substitute according to the formula.

A= 50000(1+ \frac{10}{100}{)}^{5}

<em>A=</em><em> </em><em>$80525.5</em>

Now, we can find the interest paid

\large\boxed{I= A-P}

We'll have to deduct the total amount from the principal amount.

Let's substitute according to the formula.

I= 80525.5-50000

<em>I=</em><em> </em><em>$30525.5</em>

<u>Hence</u><u>,</u><u> </u><u>the</u><u> </u><u>total</u><u> </u><u>amount</u><u> </u><u>paid</u><u> </u><u>after</u><u> </u><u>5</u><u> </u><u>years</u><u> </u><u>is</u><u> </u><u>$</u><u>80525.5</u><u> </u><u>and</u><u> </u><u>$</u><u>30525.5</u><u> </u><u>was</u><u> </u><u>paid</u><u> </u><u>as</u><u> </u><u>interest</u><u>.</u>

7 0
3 years ago
Solving quadratic equation<br>7r^2-14=-7
Gala2k [10]
I hope this helps you

7 0
4 years ago
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