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Inessa [10]
3 years ago
7

Solve the system by substitution. y = 4x y = 8x - 36

Mathematics
1 answer:
blagie [28]3 years ago
8 0

Answer:

(9,36)

Step-by-step explanation:

Substitute the 4x for the y in second equation.

Basically setting them equal to each other because the both have 'y='

4x = 8x - 36

-4x  = -36 (subtract 8x from both sides)

x = 9         (divide by -4, both sides)

y = 4(9)     (Substitute the x value into first equation)

y = 36

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Answer:

We conclude that the mean age of Canadian businesswomen has increased.

Step-by-step explanation:

We are given that according to a report released by CIBC entitled "Women Entrepreneurs: Leading the Charge," the average age for Canadian businesswomen in 2008 was 41.

The researchers randomly sample 97 Canadian businesswomen and ascertain that the sample mean age is 43.4. From past experience, it is known that the population standard deviation is 8.95.

Let \mu = <u><em>mean age of Canadian businesswomen.</em></u>

So, Null Hypothesis, H_0 : \mu \leq 41      {means that the mean age of Canadian businesswomen has decreased or remained same}

Alternate Hypothesis, H_A : \mu > 41     {means that the mean age of Canadian businesswomen has increased}

The test statistics that would be used here <u>One-sample z-test statistics</u> because we know about population standard deviation;

                               T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean age of Canadian businesswomen = 43.4

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             n = sample of Canadian businesswomen = 97

So, <u>the test statistics</u>  =  \frac{43.4-41}{\frac{8.95}{\sqrt{97} } }

                                     =  2.64

The value of z test statistic is 2.64.

<u>Also, P-value of the test statistics is given by;</u>

             P-value = P(Z > 2.64) = 1 - P(Z < 2.64)

                           = 1 - 0.99585 = <u>0.00415</u>

Now, at 1% significance level the z table gives critical value of 2.33 for right-tailed test.

Since our test statistic is more than the critical value of z as 2.64 > 2.33, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <em><u>we reject our null hypothesis</u></em>.

Therefore, we conclude that the mean age of Canadian businesswomen has increased.

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