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2 years ago

9

Please answer as soon as possible. Answers appreciated.

1 answer:

GREYUIT [131]2 years ago

6 0

Answer: $(-1.412,-2.124),(3.29,7.28)$

Step-by-step explanation:

Given

The given equation is $2^x-2.5=2x+0.7$

There are two functions i.e. $y=2^x-2.5\ \text{and}\ y=2x+0.7$

Their intersection gives the solution of the above function

From the graph, we can see that both the graph intersects at two different points i.e. at

$(-1.412,-2.124)\ \text{and}\ (3.29,7.28)$

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Can someone please help me asap

attashe74 [19]

Answer:

y=3x-4

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p

horrorfan [7]

Answer:

a = -0.3575

Step-by-step explanation:

The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.

The points A and B are located where

$y=a(x+1)(x-5)=0$

This gives

$x=-1$

$y=5$

Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

$B_x=A_x+\frac{2}{tan(60)} =-1+\frac{2\sqrt{3} }{3}$

Thus the coordinates of B are:

$B=(-1+\frac{2\sqrt{3} }{3},2)$

Now this point B lies on the parabola, and therefore it must satisfy the equation $y=a(x+1)(x-5).$

Thus

$2=a((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)$

Therefore

$a=\frac{2}{((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)}$

$\boxed{a=-0.3575}$

8 0

2 years ago

A maritime flag is shown. What is the area of the shaded part of the flag? Explain

Rom4ik [11]

Answer:

<em></em> $Area = 72in^2$ <em></em>

<em></em>

Step-by-step explanation:

<em>Your question is incomplete without an attachment (See attachment)</em>

Required

Determine the area of the shaded part

From the attachment;

<em>Assume that the shaded portion is closed to the right;</em>

<em>Calculate the Area:</em>

<em></em> $Area_1 = Length * Width$ <em></em>

<em></em> $Area_2 = 8in * (6in + 6in)$ <em></em>

<em></em> $Area_2 = 8in * 12in$ <em></em>

<em></em> $Area_1 = 96in^2$ <em></em>

<em></em>

<em>Next;</em>

<em>Calculate the Area of the imaginary triangle (on the right)</em>

<em></em> $Area_2 = \frac{1}{2} * base * height$ <em></em>

<em></em> $Area_2 = \frac{1}{2} * (6in + 6in) * 4in$ <em></em>

<em></em> $Area_2 = \frac{1}{2} * 12in * 4in$ <em></em>

<em></em> $Area_2 = \frac{1}{2} * 48in^2$ <em></em>

<em></em> $Area_2 = 24in^2$ <em></em>

<em></em>

<em>Lastly, calculate the Area of the Shaded Part</em>

<em></em> $Area = Area_1 - Area_2$ <em></em>

<em></em> $Area = 96in^2 - 24in^2$ <em></em>

<em></em> $Area = 72in^2$ <em></em>

<em></em>

<em>Hence,</em>

<em>The area of the shaded part is 72in²</em>

3 0

2 years ago

Indicate whether the function represents an exponential growth or decay.

svetoff [14.1K]

Answer:

1) decay

2) growth

3) growth

Step-by-step explanation:

A generic exponential function can be written as:

f(x) = A*(r)^x

Where:

A is the initial amount of something.

r is the rate of growth.

x is the variable, usually, represents time.

if r > 1, we have an exponential growth.

if r < 1, we have an exponential decay.

1) f(x) = (3/4)^x

in this case we have:

A = 1

r = (3/4) = 0.75

Clearly, r < 1.

Then this is an exponential decay.

2) f(x) = (1/6)*4^x

In this case we have:

A = (1/6)

r = 4

Here we have r > 1.

Then this is an exponential growth.

3) f(x) = (1/4)*(5/2)^x

in this case we have:

A = 1/4

r = 5/2 = 2.5

here we have r > 1, then this is an exponential growth.

8 0

2 years ago

Please help quickly im on a test<br> if f(x)=x+4, and g(x)=2x+4, what is f(2)+g(2)?

JulsSmile [24]

Answer:

14

Step-by-step explanation:

f(2)+g(2)

(2+4)+(2×2+4)

6+8

14

5 0

2 years ago