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3 years ago

Factor 24j - 16 to identify the equavalnet expressions

Mathematics

1 answer:

OLEGan [10]3 years ago

3 0

Answer:

Possible answers:

(24) x j - 16

8 x (3j - 2)

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How would I do part A. I showed my work but I'm slightly off

ahrayia [7]

$\bf \stackrel{\textit{perimeter of the rectangle}}{P_{rect}=2x+y}~\hfill \stackrel{\textit{area of the rectangle}}{A_{rect}=xy}
\\\\\\
\stackrel{\textit{perimeter of the semi-circle, with }r=\frac{y}{2}}{P_{semic}=\cfrac{\pi y}{2}}~\hfill \stackrel{\textit{area of the semi-circle with }r=\frac{y}{2}}{A_{semic}=\cfrac{\pi y^2}{8}}
\\\\[-0.35em]
\rule{34em}{0.25pt}$

$\bf \stackrel{\textit{perimeter of the enclosure}}{60=2x+y+\cfrac{\pi y}{2}}\implies \stackrel{\textit{multiplying by 2}}{120=4x+2y+\pi y}
\\\\\\
120-2y-\pi y=4x\implies \cfrac{120-2y-\pi y}{4}=x
\\\\[-0.35em]
\rule{34em}{0.25pt}$

$\bf \stackrel{\textit{area of the enclosure}}{A=xy+\cfrac{\pi y^2}{8}}\implies A=\left( \cfrac{120-2y-\pi y}{4} \right)y+\cfrac{\pi y^2}{8}
\\\\\\
A=\cfrac{120y-2y^2-\pi y^2}{4}+\cfrac{\pi y^2}{8}\implies A=\cfrac{240y-4y^2-2\pi y^2+\pi y^2}{8}
\\\\\\
A=\cfrac{240y-4y^2-\pi y^2}{8}\implies A=\cfrac{240y}{8}-\cfrac{4y^2}{8}-\cfrac{\pi y^2}{8}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
~\hfill A=30y-\cfrac{1}{2}y^2-\cfrac{1}{8}\pi y^2~\hfill$

5 0

3 years ago

5x(x-3)=(x-2)(5x-1)-5??

satela [25.4K]

5x(x-3) = (x-2)(5x - 1) - 5
5x^2 - 15x = 5x^2 - x - 10x + 2 - 5
5x^2 - 15x = 5x^2 - 11x - 3
5x^2 - 11x - 3 - 5x^2 + 15x = 0
4x - 3 = 0
4x = 3
x = 3/4 or 0.75

6 0

2 years ago

28 cookies out of 40 cookies are chocolate chip. What percent of the cookies are chocolate chip?

omeli [17]

Answer:

I’m pretty sure the answer would be 64%

7 0

2 years ago

Read 2 more answers

Tell whether the rates are equivalent. 0.4 kilometer for every 15 minutes 0.6 kilometer for every 20 minutes

Ostrovityanka [42]

Answer:

no they are not equivalent

Step-by-step explanation:

0.4/15 = 0.026

so for every minute they travel 0.026km

0.6/20 = 0.03

so for every minute they travel 0.03km

so they are not the same/equivalent

6 0

3 years ago

Find x<br> 25<br> 7<br> х<br> I need help

Murljashka [212]

Answer:

24 = x

Step-by-step explanation:

You use Pythagorean theorem. Since the normal equation is $a^{2} + b^{2} =c^{2}$ , you already have the $c^{2}$ and another side which can be $a^{2}$ or $b^{2}$ .

Because you have the hypotenuse and a side , your equation looks like this now: $7^{2} +b^{2} = 25^{2}$

and when you solve for be you just subtract $25^{2} -7^{2}$ to get 24.

8 0

2 years ago