Answer:
ΔU = 25.8 J
Explanation:
The gas absorbs 33.3 J of heat, that is, Q = 33.3 J.
The work (W) of expansion can be calculated using the following expression:
W = -P. ΔV
where,
P is the external pressure
ΔV is the change in volume
W = -1.45 × 10⁴ N . m⁻² × (8.40 × 10⁻⁴ m³ - 3.24 × 10⁻⁴ m³) = -7.48 J
The change in the internal energy (ΔU) is:
ΔU = Q + W
ΔU = 33.3 J + (-7.48 J) = 25.8 J
Answer:
Exclusive distribution strategy
Explanation:
Only selected retailers can sell a manufacturer's brand. Exclusive distribution can benefit manufacturers by assuring them that the most appropriate retailers represent their products.
Answer: 84.56L
Explanation:
Initial volume of gas V1 = 100L
Initial temperature T1 = 135°C
Convert temperature in Celsius to Kelvin
( 135°C + 273 = 408K)
Final temperature T2 = 72°C
( 72°C + 273= 345K)
Final volume V2 = ?
According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.
Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2
100L/408K = V2/345K
To get the value of V2, cross multiply
100L x 345K = V2 x 408K
34500 = V2 x 408K
V2.= 34500/408
V2 = 84.56L
Thus, the volume of the gas becomes 84.56 liters
Answer: The mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams
Explanation:
Depression in freezing point is given by:
= Depression in freezing point
i= vant hoff factor = 1 (for non electrolyte)
= freezing point constant =
m= molality = 
Let Mass of solute (KBr) = x g
Thus the mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams
