Newton's Second Law states:
The acceleration of an object is directly proportional to the net force acting on the object and inversely proportional to the mass of the object.
since the net force and the acceleration ar directly proportional, as the net force increases the acceleration will increase.
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Electrical?
Hope this helps
Answer : The
pH of a solution is, 8.56
Explanation : Given,
Concentration of ammonia (base) = 0.10 M
Concentration of ammonium nitrate (salt) = 0.55 M
First we have to calculate the value of 
.
The expression used for the calculation of is,
Now put the value of 
in this expression, we get:
Now we have to calculate the pOH of buffer.
Using Henderson Hesselbach equation :
![pOH=pK_b+\log \frac{[Salt]}{[Base]}](https://tex.z-dn.net/?f=pOH%3DpK_b%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BBase%5D%7D)
Now put all the given values in this expression, we get:
The pOH of buffer is 5.44
Now we have to calculate the pH of a solution.
Thus, the pH of a solution is, 8.56
Answer:
red, orange, brown, yellow, black
Explanation:
Answer:
Option D is correct = 58 g
Explanation:
Data Given:
mass of LiOH = 120 g
Mass of Li3N= ?
Solution:
To solve this problem we have to look at the reaction
Reaction:
Li₃N (s) + 3H₂0 (l) -----------► NH₃ (g) + 3LiOH (l)
1 mol 3 mol
Convert moles to mass
Molar mass of LiOH = 24 g/mol
Molar mass of Li₃N = 35 g/mol
So,
Li₃N (s) + 3H₂0 (l) -----------► NH₃ (g) + 3LiOH (l)
1 mol (35 g/mol) 3 mol (24 g/mol)
35 g 72 g
So if we look at the reaction 35 g of Li₃N react with water and produces 72 g of LiOH , then how many g of Li₃N will be react to Produce by 120 g of LiOH
For this apply unity formula
35 g of Li₃N ≅ 72 g of LiOH
X of Li₃N ≅ 120 g of LiOH
By Doing cross multiplication
Mass of Li₃N = 35 g x 120 g / 72 g
mass of Li₃N = 58 g
120 g of LiOH will produce from 58 g of Li₃N
So,
Option D is correct = 58 g
