Answer: I don't know if this helps you or not, but this is from study.com:
I'm so sorry if it doesn't:
Explanation: Iron(III) oxide reacts with carbon monoxide according to the balanced equation:
Fe₂O₃ + 3CO ➡️ 2Fe + 3CO₂
A reaction mixture initially contains 23.00g Fe₂O₃ and 15.40g CO.
Element on the right side of the periodic table differ from the elements on the left side in that elements on the <em>right side are non metallic and tends to be gases at room temperature.</em>
<em> </em><u>Explanation</u>
In the periodic table there element in the right side , left side and those which are in between.
- Example of element in the right side is fluorine chlorine, neon, Argon among others.
- This element have higher effective nuclear charges and stabilize electrons more effectively.
- there electrostatic intermolecular forces are generally weak therefore they exist in liquid or gaseous state.
Answer:
175 meters
Explanation:
As it's velocity is 35m/s
so,
by formula
35 *5
175 meters
The chemical property deals with the ability of a substance being able to burn is called combustibility [ option b ] .
<u>More</u><u> to</u><u> know</u><u> </u><u>:</u><u>-</u>
<em>1</em><em>)</em><em> </em><em>Combustion</em><em> </em><em>:</em><em>-</em>
Combustion is a chemical process in which a substance reacts rapidly with oxygen and gives out heat.
The fuel can be any one of the 3 states of matter that is - solid , liquid & gases .
Examples of combustible substances :-
Solid - Coal
Liquid - Petrol , Disel , etc.
Gas - Hydrogen , Oxygen , etc .
You can use grams to moles and moles to grams. In your case just grams to moles. So since you're given grams, you would divide that by the molar mass of CO2 because that's how many grams are in one mole. The mass for Carbon is 12.0104 g/mol and Oxygen it's 15.9994 g/mol so to find the molar mass you would add 12.0104 + (2*15.9994) which gives you a molar mass of 44.0095 g/mol. You divide your given mass (132g) by the molar mass, so there's 2.9993 moles or approximately 3 moles in 132 g of CO2.
