Un objeto de 1 kg se mueve con una velocidad cambia 10m/s¿se ha realizado trabajo sobre el objeto?
1 answer:
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Answer:
Explanation:
Attach is the solution
The magnitude of the adhesive force allows the top block to remain
attached to the bottom when the blocks and the wire are balanced.
The option that must be true is;
Reason:
The tension exerted by the wire attached to the top block = T
Magnitude of the adhesive =
Weight of the top block =
Weight of the bottom block =
Given that with the exertion of the tension, the two blocks remain at rest, we have;
- T =
+
The adhesive causes the bottom block to remain attached to the top block, we have;
Therefore, the magnitude of the adhesive force adds the bottom weight, to the top, weight, which gives;
The magnitude of the adhesive force = The weight of the bottom block
Therefore;
=
Learn more here:
The elastic potential energy of a spring is given by
where k is the spring's constant and x is the displacement with respect to the relaxed position of the spring.
The work done by the spring is the negative of the potential energy difference between the final and initial condition of the spring:
In our problem, initially the spring is uncompressed, so
. Therefore, the work done by the spring when it is compressed until 
is
And this value is actually negative, because the box is responsible for the spring's compression, so the work is done by the box.
where k is the spring's constant and x is the displacement with respect to the relaxed position of the spring.
The work done by the spring is the negative of the potential energy difference between the final and initial condition of the spring:
In our problem, initially the spring is uncompressed, so
And this value is actually negative, because the box is responsible for the spring's compression, so the work is done by the box.