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3 years ago

Un objeto de 1 kg se mueve con una velocidad cambia 10m/s¿se ha realizado trabajo sobre el objeto?

Physics

1 answer:

Wewaii [24]3 years ago

6 0

Answer:

I don't speak spanish oso sorry

Explanation:

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3 years ago

QuestionDetails:

sleet_krkn [62]

To solve the two parts of this problem, we will begin by considering the expressions given for gravitational potential energy and finally kinetic energy (to find velocity). From the potential energy we will obtain its derivative that is equivalent to the Force of gravitational attraction. We will start considering that all the points on the ring are same distance:

$r = \sqrt{x^2+R^2}$

Then the potential energy is

$U = \frac{-GMm}{\sqrt{x^2+R^2}}$

PART A) The force is excepted to be along x-axis.

Therefore we take a derivative of U with respect to x.

$F = -\frac{dU}{dx}$

$F = -\frac{d}{dx}(GMm(\frac{1}{R}-\frac{1}{\sqrt{x^2+R^2}}))$

$F = \frac{GMmx}{(x^2+R^2)^{3/2}}$

This expression is the resultant magnitude of the Force F.

PART B) The magnitude of loss in potential energy as the particle falls to the center

$U = GMm(\frac{1}{R}-\frac{1}{\sqrt{x^2+R^2}})$

According to conservation of energy,

$\frac{1}{2}mv^2 = GMm (\frac{1}{R}-\frac{1}{\sqrt{x^2+R^2}})$

$\therefore v = \sqrt{2GM(\frac{1}{R}-\frac{1}{x^2+R^2})}$

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3 years ago

WHAT IS THE POTENIAL ENERGY OF A 3 KILOGRAM BALL THAT IS ON THE GROUND

Ratling [72]

Answer:

147.15 Joules.

Explanation:

A 3 kilogram mass at a height of 5 meters, while acted on by Earth's gravity would have 147.15 Joules of potential energy, PE = 3kg * 9.81 m/s2 * 5m = 147.15 J.

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2 years ago

Which figure shows a correct pattern of electric field lines?

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Where are the figures?

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3 years ago

Un objeto de 1 kg se mueve con una velocidad cambia 10m/s¿se ha realizado trabajo sobre el objeto?​

Un objeto de 1 kg se mueve con una velocidad cambia 10m/s¿se ha realizado trabajo sobre el objeto?