Answer:
p(2) =147 and p(4) = 1791
Step-by-step explanation:
We are given p(x)= 6x^4 + 4x^3 – 3x^2 + 8x + 15.
Now we need to find value of p(2) and p(4)
Put x =2,
p(2) = 6(2)^4 + 4(2)^3 – 3(2)^2 + 8(2) + 15
p(2) = 6(16)+4(8)-3(4)+8(2)+15
p(2) = 96+32-12+16+15
p(2) = 147
Now put x = 4
p(4) = 6(4)^4 + 4(4)^3 – 3(4)^2 + 8(4) + 15
p(4) = 6(256)+4(64)-3(16)+8(4)+15
p(4) = 1536+256-48+32+15
p(4) = 1791
Answer:
45
Step-by-step explanation:
Since this is only three terms
Find the three terms and add
j=1 3(1)^2+1 = 3+1 =4
j=2 3(2)^2+1 = 3(4)+1 =13
j=3 3(9)^2+1 = 27+1 =28
The sum is 4+13+28 =45
Answer:
r⁶
Step-by-step explanation:
Cancel the common factors or r⁹ and r³
Answer:
x= -7/8
Step-by-step explanation:
8x + 7 = 0
8x + 7-7 = 0-7
8x=-7
8x/8x = -7/8
