<span>When you do work on a object some of your energy is "Transfers" to that object.
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Answer:
The magnitude of the new electric field is <u>35820 N/C</u>.
Explanation:
Given:
Original magnitude of electric field (E₀) = 2388 N/C
Original voltage = 'V' (Assume)
Original separation between the plates = 'd' (Assume)
Now, new voltage is three times original voltage. So, 
New distance is 1/5 the original distance. So, 
Now, electric field between the parallel plates originally is given as:
Let us find the new electric field based on the above formula.
Now, 
. So,
Therefore, the magnitude of the new electric field is 35820 N/C.
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A force of 5.5N is applied to an object. The moment arm for the force is 0.84 m, the torque produced by the force is <u>4.62N-m</u>.
A force applied perpendicularly to a lever multiplied by its distance from the lever's fulcrum (the length of the lever arm) is its torque. We can find the torque from a force by taking the perpendicular component of that force and multiplying by the magnitude of the R vector where this R vector is the vector that points from the axis to the point where the force is applied.
To calculate torque produced by the force, we have-
Torque= forcexmoment arm
T = fxd
T =5.5Nx0.84m
T=4.62N-m.
To learn more about torque, visit---
brainly.com/question/20691242
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