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2 years ago

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The escape velocity of a bullet from the surface of planet Y is 1695.0 m/s. Calculate the escape velocity from the surface of th

e planet X if the mass of planet X is 1.59 times that of Y, and its radius is 0.903 times the radius of Y.

1 answer:

serg [7]2 years ago

6 0

The escape velocity from the surface of the planet X is 2,249.2 m/s.

<h3>Escape velocity of planet X</h3>

$v = \sqrt{\frac{2GM}{r} } \\\\v^2 = \frac{2GM}{r}\\\\v^2r = 2GM\\\\G = \frac{v^2r}{2M}$

where;

M is mass of the planet
r is radius of the planet
G is universal gravitation constant

$\frac{v_x^2 \ r_x}{2M_x} = \frac{v_y^2 \ r_y}{2M_y} \\\\\frac{v_x^2 \ r_x}{M_x} = \frac{v_y^2 \ r_y}{M_y} \\\\v_x^2 = \frac{v_y^2 \ r_yM_x}{M_yr_x}\\\\v_x^2 = \frac{(1695)^2 (r_y)(1.59M_y)}{M_y(0.903r_y)} \\\\v_x^2 = 5,058,814.78\\\\v_x = \sqrt{5,058,814.78} \ \ = 2,249.2 \ m/s$

Thus, the escape velocity from the surface of the planet X is 2,249.2 m/s.

Learn more about escape velocity here: brainly.com/question/13726115

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PART C)

Volume of the sphere is given as

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4 years ago

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Answer:

Se obtienen 2,27 gramos de metanol.

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Para encontrar el reactivo limitante y el reactivo en exceso, debemos calcular el número de moles de CO y H₂:

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En donde:

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M: es el peso molecular

$\eta_{CO} = \frac{m}{M_{CO}} = \frac{2,0 g}{28,01 g/mol} = 0,071 moles$

$\eta_{H_{2}} = \frac{2,0 g}{2,02 g/mol} = 0,99 moles$

Dado que la relación estequiométrica entre CO y H₂ es 1:2, el número de moles de hidrógeno gaseoso que reaccionan con el monóxido de carbono es:

$\eta_{H_{2}} = \frac{2}{1}*0,071 = 0,142 moles$

Entonces, se necesitan 0,142 moles de H₂ para reaccionar con 0,071 moles de CO y debido a que se tienen más moles de H₂ (0,99 moles) entonces el reactivo limitante es CO y el reactivo en exceso es H₂.

Ahora podemos encontar la masa de metanol obtenida usando el reactivo limitante (CO) y sabiendo que la realcion estequiométrica entre CO y CH₃OH es 1:1.

$\eta_{CH_{3}OH} = \eta_{CO} = 0,071 moles$

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Por lo tanto, se obtienen 2,27 gramos de metanol.

Espero que te sea de utilidad!

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