<span>Data:
mass =
110-g bullet
d = 0.636 m
Force =
13500 + 11000x - 25750x^2, newtons.
a) Work, W
W = ∫( F* )(dx) =∫[13500+ 11000x - 25750x^2] (dx) =
W = 13500x + 5500x^2 - 8583.33 x^3 ] from 0 to 0.636 =
W = 8602.6 joule
b) x= 1.02 m
</span><span><span>W = 13500x + 5500x^2 - 8583.33 x^3 ] from</span> 0 to 1.02
W = 10383.5
c) %
[W in b / W in a] = 10383.5 / 8602.6 = 1.21 => W in b is 21% more than work in a.
</span>
The last equation gives you the tension in the string on the right:

Answer:
pulling a muscle. putting too much strain on a muscle causing a tear.
Explanation:
Doing warm ups help your muscles adjust to the full extent of a basketball game. Warming up is like stretching, helps your muscles adjust before going full out on the court.
Answer:
The final equilibrium T_{f} = 25.7[°C]
Explanation:
In order to solve this problem we must have a clear concept of heat transfer. Heat transfer is defined as the transmission of heat from one body that is at a higher temperature to another at a lower temperature.
That is to say for this case the heat is transferred from the iron to the water, the temperature of the water will increase, while the temperature of the iron will decrease. At the end of the process a thermal balance is found, i.e. the temperature of iron and water will be equal.
The temperature of thermal equilibrium will be T_f.
The heat absorbed by water will be equal to the heat rejected by Iron.

Heat transfer can be found by means of the following equation.

where:
Qiron = Iron heat transfer [kJ]
m = iron mass = 200 [g] = 0.2 [kg]
T_i = Initial temperature of the iron = 300 [°C]
T_f = final temperature [°C]

Cp_iron = 437 [J/kg*°C]
Cp_water = 4200 [J/kg*°C]
![0.2*437*(300-T_{f})=1*4200*(T_{f}-20)\\26220-87.4*T_{f}=4200*T_{f}-84000\\26220+84000=4200*T_{f}+87.4*T_{f}\\110220 = 4287.4*T_{f}\\T_{f}=25.7[C]](https://tex.z-dn.net/?f=0.2%2A437%2A%28300-T_%7Bf%7D%29%3D1%2A4200%2A%28T_%7Bf%7D-20%29%5C%5C26220-87.4%2AT_%7Bf%7D%3D4200%2AT_%7Bf%7D-84000%5C%5C26220%2B84000%3D4200%2AT_%7Bf%7D%2B87.4%2AT_%7Bf%7D%5C%5C110220%20%3D%204287.4%2AT_%7Bf%7D%5C%5CT_%7Bf%7D%3D25.7%5BC%5D)
The correct answer is B. The addition of oxygen will increase the rate of combustion. oxygen and raw material (fuel) are the substrates for the combustion process, therefore, increase in the same will obviously increase combustion rate. Carbon in the fuel is converted into carbon dioxide and heat.