k = spring constant of the spring = 100 N/m
m = mass hanging from the spring = 0.71 kg
T = Time period of the spring's motion = ?
Time period of the oscillations of the mass hanging is given as
T = (2π) √(m/k)
inserting the values in the above equation
T = (2 x 3.14) √(0.71 kg/100 N/m)
T = (6.28) √(0.0071 sec²)
T = (6.28) (0.084) sec
T = 0.53 sec
hence the correct choice is D) 0.53
Answer:
Explanation:
g means gravitation
G is universal gravitational constant
M = mass of the earth
R = radius of the earth
Hope this helps
plz mark as brainliets!!!!!!!!!
Sand
dead creatures
polluted coral reefs will die
REMEMBER...CORAL ARE LIVING
Answer:
In a column of fluid, pressure increases with depth as a result of the weight of the overlying fluid. Thus a column of fluid, or an object submerged in the fluid, experiences greater pressure at the bottom of the column than at the top. This difference in pressure results in a net force that tends to accelerate an object upwards.
The pressure at a depth in a fluid of constant density is equal to the pressure of the atmosphere plus the pressure due to the weight of the fluid, or p = p 0 + ρ h g , p = p 0 + ρ h g , 14.4
Granite: 2.70 × 10 32.70 × 10 3
Lead: 1.13 × 10 41.13 × 10 4
Iron: 7.86 × 10 37.86 × 10 3
Oak: 7.10 × 10 27.10 × 10 2
<h2>
Answer:</h2>
800gm
<h2>
Explanation:</h2>
Archimedes principle states that when an object is immersed in a liquid there is an apparent loss of weight of the object. This apparent loss of weight is also the upthrust experienced by the liquid. The upthrust is equal to the weight of the liquid displaced.
Following from the above statement, when the body of volume 100c.c is immersed in the water contained in the jar, the upthrust experienced is equal to the weight of the water displaced.
<em>Note: In the question, weight is measured just using the mass.</em>
Mass (m) is the product of density (ρ) of liquid (which is water in this case) and volume (v) of body immersed. i.e
m = ρ x v
Where;
ρ = 1 gm/cm³
v = 100c.c = 100cm³
=> m = 1 gm/cm³ x 100cm³
=> m = 100gm
Therefore the weight of water displaced is 100gm
Now, the weight of the water and jar after immersion is the sum of the weight of water and jar before immersion, and the weight of the water displaced. i.e
Weight of water and jar after immersion = 700gm + 100gm = 800gm
