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Nina [5.8K]
4 years ago
11

Does wve travel faster through glass or air

Physics
1 answer:
balandron [24]4 years ago
8 0
The answer is glass.
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A father wanted to explain how the moon shines to his 5-year old child by comparing it to an object that the child uses. Which s
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The moon is like a mirror. It reflects light produced by the Sun

Explanation:

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3 years ago
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Two objects gravitationally attract with a force of 10N. If the distance between the two objects center is doubled, then the new
lana [24]

Answer:

20N

Explanation:

10×2

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3 years ago
When designing an experiment, why is it important to test only one variable?
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That's the only way you can get consistent and accurate results. 
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A person stands on the ball of one foot. The normal force due to the ground pushing up on the ball of the foot has magnitude 750
White raven [17]

Answer:

the force exerted on the foot by the tibia would be 2975 N

Explanation:

Given the data in the question;

To maintain equilibrium between the foot and the ball vertically, the addition normal normal force N^> (750 N)  and the tension in the Achilles tendon F^>_{Achilles} (2225 N) must be equal to the force exerted on the foot by the tibia;

so

| N^> | + |F^>_{Achilles} | = | F^>_{Tibia} |

so force exerted on the foot by the tibia will be;

| F^>_{Tibia} | = |N^> | + |F^>_{Achilles} |

so we substitute IN OUR VALUES

| F^>_{Tibia} | = 750 N + 2225 N

| F^>_{Tibia} |  = 2975 N

Therefore, the force exerted on the foot by the tibia would be 2975 N

3 0
3 years ago
To stop a car, first you require a certain reaction time to begin braking; then the car slows under the constant braking deceler
ANEK [815]

Answer:

a) t_r = 0.55 s

b) a = 5.59 m/s²

Explanation:

given,

total distance traveled by the car to stop is 56.9 m when speed of vehicle is 80 km/h or 80 × 0.278 = 22.24 m/s

total distance traveled by the car to stop is 25.7 m when speed of vehicle is 50.7 km/h or 50.7 × 0.278 = 14.09 m/s

using stopping distance formula

s_1 = v_1 t_r +\dfrac{v_1^2}{2 a}................(1)

s_2 = v_2 t_r +\dfrac{v_2^2}{2 a}..............(2)

on solving both the equation we get

a = \dfarc{v_1v_2(v_1-v_2)}{2(s_1v_2-s_2v_1)}

a = \dfarc{22.4\times 14.09(22.24-14.09)}{2(56.9\times 14.09-25.7\times 22.24)}

a = 5.59 m/s²

now reaction time calculation

t_r =\dfrac{v_1^2d_2-v_2^2d_1}{v_1v_2(v_1-v_2)}

t_r =\dfrac{22.24^2\times 25.7-14.09^2\times 56.9}{22.4\times 14.09(22.24-14.09)}

t_r = 0.55 s      

8 0
3 years ago
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