Answer:
can u explain it more lol
Step-by-step explanation:
Answer:
- <u>Hannah was not speeding because her speed was about 61 mph, which is below the speed limit.</u>
Explanation:
Just to correct some typos, this is the complete question:
<em />
<em>The equation d=0.05v² + 1.1v models the distance, d, that it takes a car traveling at a speed of v miles per hour to come to a complete stop. If Hannah’s car stopped after travelling 250 feet on a highway with a speed limit of 65 mph, was Hannah speeding? Explain using math whether she was speeding and how you know.</em>
<em />
<h2>Solution</h2>
<em />
To find whether Hannah was speeding, you must find the velocity that is solution for the equation:
<em />
Write it in standard form:
Use the quadratic formula:



The speed can only be positive; thus, it is about 61 miles per hour, which is below the speed limit of 65mph.
In conclusion, she was not speeding.
Answer:
I THINK a=3 b=9
Step-by-step explanation:
Answer:
0.8989
Step-by-step explanation:
Using the Newton's Raphson approximation formula.
Xn+1 = Xn - f(Xn)/f'(Xn)
Given f(x) = x³-2x+2
f'(x) = 3x²-2
If the initial value X1 = 2
X2 = X1 - f(X1)/f'(X1)
X2 = 2 - f(2)/f'(2)
f(2) = 2³-2(2)+2
f(2) = 8-4+2
f(2) = 6
f'(2) = 3(2)²-2
f'(2) = 10
X2 = 2- 6/10
X2 = 14/10
X2 = 1.4
X3 = X2 - f(X2)/f'(X2)
X3 = 1.4 - f(1.4)/f'(1.4)
f(1.4) = 1.4³-2(1.4)+2
f(1.4) = 2.744-2.8+2
f(1.4) = 1.944
f'(1.4) = 3(1.4)²-2
f'(1.4) = 3.880
X3 = 1.4- 1.944/3.880
X3 = 1.4 - 0.5010
X3 = 0.8989
Hence the value of X3 is 0.8989
Answer:
here's your answer
hope this helped you
please mark as the brainliest (ㆁωㆁ)