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zalisa [80]
3 years ago
6

Can anyone please help me out?

Mathematics
1 answer:
dem82 [27]3 years ago
4 0
I think D is the answer
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Find the area of a triangle with sides a = 5, b = 8, and c = 11
Sergio039 [100]
Well the formula for a triangle is base(b) times height(h) divided by 2.

6 0
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What is the length of the diagonal of a rectangle that is 12 inches long and 6 inches wide?​
lakkis [162]
To find the diagonal of the rectangle we have to use Pythagorean theorem!

Pythagorean theorem is used to find the length of a missing angle such as the hypotenuse or the sides a and b.

Steps to solve:

1. 12 in is the length or the base of the right triangle, and 6 in is the wide or the side a.
2. Now use the formula: a^2+b^2=c^2, and plug in the numbers!
3. 6^2+12^2=c^2, now just solve the squared numbers.
4. 36+144=c^2
5. 180=c^2
6. Find the square root of 180.

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4 0
3 years ago
Use the Distributive Property​ to simplify the expression<br> 4(​c​ - 2)
xeze [42]

Answer

Step-by-step explanation:

4xc=4c

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4c-8

3 0
3 years ago
ILL GIVE BRAINLIEST!!!!! <br> write a subtraction number line model. -10 -8 -6 -4 -2 0 2 4 6 8 10
velikii [3]

Answer:

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8 0
3 years ago
If the sum of 4040 consecutive integer numbers is 2020, find out the absolute difference between the first number and the last n
bearhunter [10]

Let x be the smallest of the consecutive integers summing to 2020. Then the largest integer in the sum is x+4039, so our answer is \boxed{4039}.

For completeness, though, let's solve for the value of x that satisfies the conditions of the problem. Recall that the sum of an arithmetic series with first term a_1, last term a_n, and n terms, is \frac{n(a_1+a_n)}{2}. Plugging in our known values gives us the equation \frac{4040(2x+4039)}{2}=2020, which simplifies to 2x+4039=1. Thus, x=-2019, so the 4040 consecutive integers are -2019,-2018,\dots,-1,0,1,\dots,2018,2019,2020. Notice how everything except the 2020 cancels out!

4 0
3 years ago
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