Answer:
top row on 9 page; 9) 53/5 10) 26/4 11) 37/4
bottom row on 9 page; 9) 8 and 1/7 10) 6 and 3/4 11) 1 and 1/3
top row on 3 page; 3) 2 and 2/7 4) 5 and 3/4 5) 8 and 1/10
bottom row on 3 page; 3) 4/3 4) 3/2 5) 12/5
top row on 12 page; 12) 21/10 13) 62/6 14) 57/6
bottom row on 12 page; 12) 1 and 9/10 13) 10 and 1/2 14) 3 and 3/8
Step-by-step explanation:
You never specified if these had to be simplified or turned into a fraction, so I just simplified them. That's about it.
I hope this helps :)
Answer:
The expression to compute the amount in the investment account after 14 years is: <em>FV</em> = [5000 ×(1.10)¹⁴] + [3000 ×(1.10)⁸].
Step-by-step explanation:
The formula to compute the future value is:
![FV=PV[1+\frac{r}{100}]^{n}](https://tex.z-dn.net/?f=FV%3DPV%5B1%2B%5Cfrac%7Br%7D%7B100%7D%5D%5E%7Bn%7D)
PV = Present value
r = interest rate
n = number of periods.
It is provided that $5,000 were deposited now and $3,000 deposited after 6 years at 10% compound interest. The amount of time the money is invested for is 14 years.
The expression to compute the amount in the investment account after 14 years is,
![FV=5000[1+\frac{10}{100}]^{14}+3000[1+\frac{10}{100}]^{14-6}\\FV=5000[1+0.10]^{14}+3000[1+0.10]^{8}](https://tex.z-dn.net/?f=FV%3D5000%5B1%2B%5Cfrac%7B10%7D%7B100%7D%5D%5E%7B14%7D%2B3000%5B1%2B%5Cfrac%7B10%7D%7B100%7D%5D%5E%7B14-6%7D%5C%5CFV%3D5000%5B1%2B0.10%5D%5E%7B14%7D%2B3000%5B1%2B0.10%5D%5E%7B8%7D)
The future value is:
![FV=5000[1+0.10]^{14}+3000[1+0.10]^{8}\\=18987.50+6430.77\\=25418.27](https://tex.z-dn.net/?f=FV%3D5000%5B1%2B0.10%5D%5E%7B14%7D%2B3000%5B1%2B0.10%5D%5E%7B8%7D%5C%5C%3D18987.50%2B6430.77%5C%5C%3D25418.27)
Thus, the expression to compute the amount in the investment account after 14 years is: <em>FV</em> = [5000 ×(1.10)¹⁴] + [3000 ×(1.10)⁸].
Answer:
25. Its cubed.
Step-by-step explanation:
Answer:
<h2>D= 3.9 miles</h2>
Step-by-step explanation:
Given data
speed v= 13 miles per hour
time taken t= 20min to hour 0.3 hours
the distance D
We know that the relationship between speed, time, and distance
speed=distance/time
13=D/0.3
(the expression above describes the relationship between distance, speed, and time)
making D subject of formula we have
D= 0.3*13
D= 3.9 miles
hence the distance is 3.9miles
Answer:
A =First term of the pattern = 11
To find the first five terms we have to use the rule which is
Add 10 to first term and then subtract 5 from it.Which is equivalent to
= A +10 -5
1. Second Term = 11 + 10 -5
= 21 - 5
=16
→Third term = 16 +10-5
= 26 - 5
= 21
→Fourth term : 21 + 10 - 5
= 31 -5
= 26
→Fifth term : 26 +10 -5
= 36- 5
= 31
→Sixth term:
=31 + 10- 5
= 41 -5
= 36
So, the first five term apart from 11 is 16, 21,26,31,36 which is an Airthmetic progression.
