Answer:
(A) Yes, since the test statistic is in the rejection region defined by the critical value, reject the null. The claim is the alternative, so the claim is supported.
Step-by-step explanation:
Null hypothesis: The wait time before a call is answered by a service representative is 3.3 minutes.
Alternate hypothesis: The wait time before a call is answered by a service representative is less than 3.3 minutes.
Test statistic (t) = (sample mean - population mean) ÷ sd/√n
sample mean = 3.24 minutes
population mean = 3.3 minutes
sd = 0.4 minutes
n = 62
degree of freedom = n - 1 = 62 - 1 = 71
significance level = 0.08
t = (3.24 - 3.3) ÷ 0.4/√62 = -0.06 ÷ 005 = -1.2
The test is a one-tailed test. The critical value corresponding to 61 degrees of freedom and 0.08 significance level is 1.654
Conclusion:
Reject the null hypothesis because the test statistic -1.2 is in the rejection region of the critical value 1.654. The claim is contained in the alternative hypothesis, so it is supported.
If \dfrac{x-1}{3}=k 3 x−1 =kstart fraction, x, minus, 1, divided by, 3, end fraction, equals, k and k=3k=3k, equals, 3, what i
earnstyle [38]
For this case we have the following expression:
(x-1) / (3) = k
Substituting the value of k = 3 we have:
(x-1) / (3) = 3
From here, we must clear the value of x.
We have then:
x-1 = 3 * 3
x-1 = 9
x = 9 + 1
x = 10
Answer:
The value of x is given by:
x = 10
Answer: it’s very good imo
Can you try to put them I order?
