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3 years ago

Add: 3x(x-y+z) and 2y (x+y-z)

Mathematics

2 answers:

GREYUIT [131]3 years ago

4 0

Answer:

Step-by-step explanation:

hello :

3x(x-y+z) + 2y (x+y-z) = 3x²-3xy+3xz +2yx+2y²-2yz

3x(x-y+z) + 2y (x+y-z) = 3x² -xy+3xz -2yz+2y²

hodyreva [135]3 years ago

3 0

Answer:

3x^2 + 3xz + 2y^2 - 2yz - xy

Step-by-step explanation:

(1) multiply it to get

3x^2 - 3xy + 3xz and 2yx + 2y^2 - 2yz

add similar variables (-3xy + 2yx)

( the order of the variables doesn't matter xy or yx is the same)

we get -xy

and then after that simplifying we get 3x^2 + 3xz + 2y^2 - 2yz - xy

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1 year ago

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3 years ago

Which numbers are a distance of 4 units from 7 on the number line?

gayaneshka [121]

On the number line, 3 and 11 are the numbers that are a distance of 4 units from 7..

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We have been asked the numbers which are a distance of 4 units from 7 on the number line.

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Learn more about the number line here: brainly.com/question/77754

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2 years ago

What is the distance between (8, -3) and (4, -7)?

nirvana33 [79]

The answer is √32 units.

please see the attached picture for full solution

Hope it helps

Good luck on your assignment

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3 years ago

Add: 3x(x-y+z) and 2y (x+y-z)​

Add: 3x(x-y+z) and 2y (x+y-z)