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3 years ago

And this one please thank you.

Chemistry

1 answer:

slavikrds [6]3 years ago

7 0

Answer:

Explanation:

Look at bottom numbers.

90 → 88 + x

it means,

90=88+x

hence x = 2

it is also valid for top numbers.

230=226+y

y = 4

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The rotten smell of a decaying animal carcass is partially due to a nitrogen-containing compound called putrescine. Elemental an

guajiro [1.7K]

Answer:

$C_2H_6N$

Explanation:

Hello,

In this case, considering the given percentages, we compute the mole ratios as shown below:

$n_C=\frac{0.545}{12}=0.0454\\n_H=\frac{0.1373}{1}=0.1373\\n_N=\frac{0.3177}{14}=0.0227$

Now, by dividing all the mole ratios by the smallest ratio, we obtain the subscripts for the required empirical formula as shown below:

$C=\frac{0.0454}{0.0227} =2\\H=\frac{0.1373}{0.0227}=6\\N=\frac{0.0227}{0.0227}=1$

Therefore, the empirical formula turns out:

$C_2H_6N$

Best regards.

8 0

3 years ago

Easy points

Anni [7]

Answer:

Magnesium, strontium, and barium belong to group 2A of the periodic table.

7 0

3 years ago

Diffrentiate the reactivity of metals and Non-metals with air / oxygen.

algol13

Answer:

Both metals and non-metals when burnt in oxygen form their oxides. Oxides of metals are basic in nature and oxides of non-metals are acidic in nature.

8 0

2 years ago

which of the following is a composite of a gas and a solid? A.) an apple B.) sediment moving in a river C.) water vapor in the a

AURORKA [14]

The answer is D.

The air inside the bubbles is gas and the solid forms the bubble.

6 0

3 years ago

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In the reaction between Lithium Sulfate and an excess of Lead (II) Nitrate, how many molecules of Lithium Nitrate can be expecte

siniylev [52]

Answer:

$1.46x10^{23}molecules \ LiNO_3$

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

$Li_2SO_4 + Pb(NO_3)_2 \rightarrow PbSO_4+2LiNO_3$

Thus, since lead (II) nitrate is in excess, we can directly compute the moles of lithium nitrate by applying the 1:2 molar ratio between them in the chemical reaction as well as the molar mass of Lithium Sulfate that is 110 g/mol for the stoichiometric shown below factor:

$n_{LiNO_3}=13.3gLi_2SO_4*\frac{1molLi_2SO_4}{110gLi_2SO_4} *\frac{2molLiNO_3}{1molLi_2SO_4} =0.242molLiNO_3$

Finally, by using the Avogadro's number we are able to compute the molecules:

$0.242molLiNO_3*\frac{6.022x10^{23}molecules\ LiNO_3}{1mol}=1.46x10^{23}molecules \ LiNO_3$

Best regards.

5 0

4 years ago

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