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2 years ago

Which of the following would make a solution?

Chemistry

2 answers:

gizmo_the_mogwai [7]2 years ago

8 0

Answer:

B sugar in water

Explanation:

because sugar dissolves in water while the others don't

Oliga [24]2 years ago

5 0

B. Sugar in water
Sugar dissolves in water

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Dihydrogen monoxide is a(n) ____. A. covalent compound B. molecular formula C. empirical formula D. Ionic compound

olga_2 [115]

Answer:

D. Ionic compound

Explanation:

Just based on my opinion

Correct me if I'm wrong tnx:<

8 0

2 years ago

How many atoms of hydrogen and oxygen are present in 5 gm of HNO3

Rufina [12.5K]

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6 0

3 years ago

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How many mols are present in the a sample of silver nitrate which has<br> 5.3x10^24 molecules.

Westkost [7]

Answer: 5.3 x 10^24 formula units of silver nitrate is equivalent to 8.8 moles of silver nitrate. Silver nitrate is an ionic compound, therefore, its representative particle is called a "formula unit" instead of molecule. For every mole of a substance, we know that there are 6.022 x 10^23 representative units of that substance. The amount of particles in one mole of substance is called Avogadro's number.

Further Explanation:

We can convert from number of representative particles to moles using the formula:

$\boxed {no. \ of \ moles \ = \ ( given \ no. \ of \ particles) \ (\frac{1 \ mole}{\ 6.022 \ x 10^{23} particles})}$

For this problem, we can calculate the number of moles by plugging in the given values to the equation above,

$no. \ of \ moles \ = (5.3 \ x \ 10^{24} \ formula \ units \ AgNO_{3}) \ (\frac{1 \ mole \ AgNO_{3}}{6.022 \ x 10^{23} \ formula \ units AgNO_{3}}) \\\\\boxed {no. \ of moles \ AgNO_{3} \ = \ 8.8 \ moles}$

Learn More

Learn more about representative particles brainly.com/question/8969313
Learn more about Avogadro's number brainly.com/question/229300
Learn more about mole conversions brainly.com/question/1370888

Keywords: moles conversion, Avogadro's number

5 0

3 years ago

Methane, the principal component of natural gas, is used for heating and cooking. The combustion process is CH4(g) + 2 O2(g) → C

antoniya [11.8K]

Answer:

392.97 litres

Explanation:

From the equation of reaction, we can see that 1 mole of methane yielded 1 mole of carbon iv oxide. Hence, 15.9 moles of methane will yield 15.9 moles of carbon iv oxide.

At s.t.p one mole of a gas occupies a volume of 22.4L ,hence 15.9 moles of a gas will occupy a volume of 22.4 × 15.9 which equals

356.16L.

Now, we can use the general gas equation to get the volume produced at the values given.

We have the following values;

V1 = 356.16L P1= 1 atm ( standard pressure) T1 = 273K ( standard temperature) V2 = ? T2 = 23.7 + 273 = 296.7K P2 = 0.985 atm

The general form of the general gas equation is given as :

(P1V1)T1 = (P2V2)/T2

After substituting the values , we get V2 to be 392.97Litres

8 0

3 years ago

What is the pOH of a base with a OH- concentration of 0.0500 x 10-11 M? PLEASEEEEEE ASAP

Ksivusya [100]

Answer:

poH= -log(oh^-)

= - log (0.500* 10^-11)

= =- log 0.5 + log (10^-11)

= -( -0.30 +(-11))

=+ 11.3

4 0

3 years ago