Answer:
b. the stage
Step-by-step explanation:
The stage typically has a stage clip on either side to hold the slide firmly in place.
6, Bob will have 6 apples after he gives 14 away.
To solve this problem, we must first understand what it is asking. Since Bob is giving away apples, he is subtracting them from his total amount. So, now we do the subtraction.
20 - 14 = 6, so Bob will have 6 apples after he gives 14 away.
The first problem:y = -2 x² ⇒⇒⇒ x² = -y/2 →(1)33 x² + y² = 27 → (2)
By substitution from (1) at (2) with the value of x²
∴ 33 (-y/2) + y² = 27
∴ y² - 16.5 y - 27 = 0
a = 1 , b = -16.5 , c = -27
∴

∴ y = 18 or y = -3/2
By substitution from at (1) with the value of y
for y = 18 ⇒⇒⇒ x² = -18/2 = -9 (unacceptable)
for y = -3/2 ⇒⇒⇒ x² = -(-3/2)/2 = 3/4
∴

The correct options are 2 , 7
Solution of the system of equations is

and

==================================
The second problem:
The general equation of the hyperbole is

For the given equation:

a² = 225 ⇒⇒⇒ a = √225 = 15
b² = 36 ⇒⇒⇒ b = √36 = 6
∴ the slope of the <span><span>asymptotes = </span>b/a and -b/a
</span><span>
</span><span>b/a = 6/15 = 2/5
</span><span>
</span><span>-b/a = -6/15 = -2/5
</span><span>
</span><span>∴ m = 2/5 and m = -2/5
</span>
5.
when i rolled a dice it was 5.
1. (-6, -6) (-2, -4) (-2, -6)
Write under each set (+6)
2. F" (-6, 0) G" (-2, 2) H" (-2,0)