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Montano1993 [528]
1 year ago
13

Identify whether the equation represents an exponential growth or exponential decay function.1. y = 1/4 (1/e)^-2x2. y = (1/e)^4x

3. y = 2e^-x + 1How do you do this?
Mathematics
1 answer:
zvonat [6]1 year ago
5 0

The general formula for exponential growth and decays is:

y=y_0e^{kx}

if k>0 then then it is an exponential growth function. If k<0 then the function represents an exponential decay.

Now we need to classify each of the functions:

1.

The function

y=\frac{1}{4}(\frac{1}{e})^{-2x}

can be wrtten as:

\begin{gathered} y=\frac{1}{4}(e^{-1})^{-2x}^{} \\ =\frac{1}{4}e^{2x} \end{gathered}

comparing with the general formula we notice that k=2, therefore this is an exponential growth.

2.

The function

y=(\frac{1}{e})^{4x}

can be written as:

\begin{gathered} y=(\frac{1}{e})^{4x} \\ y=(e^{-1})^{4x} \\ y=e^{-4x} \end{gathered}

comparing with the general formula we notice that k=-4, therefore this is an exponential decay.

3.

The function

y=2e^{-x}+1

comparing with the general formula we notice that k=-1, therefore this is an exponential decay.

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The probability of randomly selecting a name starting with the letter T from bowl of 24 names depends on the names that are in the bowl,. The number 24 says nothing about the names. There can be neither probability that the randomly selected name starts with T, if in the bowl none of the 24 names starts with T. 
It could be also unlikely to select a name starting with T if there is a really small number of names in the bowl starting with T (for example 1 or 2 from 24). And it can be likely to chose a name  that start with T if there are many names in the bowl starting with T.So, it is important to know the number of names in the bowl starting with T. 
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3 years ago
state domain and range, intercepts, relative max and relative mins points and values, intervals of increase and decrease, interv
Anarel [89]

The domain of the graph is -∝ < x < ∝ and the range of the graph is -∝ < y < ∝. Also, the graph has no axis of symmetry

<h3>The domain and range of the graph</h3>

From the graph, we can see that the x values extend indefinitely

So, the domain of the graph is -∝ < x < ∝

From the graph, we can see that the y values extend indefinitely

So, the range of the graph is -∝ < y < ∝

<h3>The intercepts</h3>

This is where the graph crosses the axes

So, we have the intercepts to be

  • x-intercept = -4, -2 and 2
  • y-intercept = -9

<h3>Relative max and relative mins points and values, </h3>

The graph has a relative maximum at (3, 3) and the relative minimum are (0.5, 10)

<h3>Intervals of increase and decrease, </h3>

There are the intervals where the function increases and decreases

So, we have the intervals to be

  • Increasing interval: (0.5, ∝) and (-∝, -3)
  • Decreasing interval: (-3, 0.5)

<h3>Intervals of positive and negative,</h3>

There are the intervals where the function is positive and negative

So, we have the intervals to be

  • Positive interval: (-4, -2) and (2, ∝)
  • Negative interval: (-∝, -4) and (-2, 2)

<h3>The symmetry</h3>

This is the line that divides the graph equal part

In this case, the graph has no axis of symmetry

<h3>The end behavior</h3>

Using the intervals where the function is positive and negative, the end behavior is

  • As x ⇒ ∝, f(x) ⇒ +∝
  • As x ⇒ -∝, f(x) ⇒ -∝

Read more about functions at:

brainly.com/question/3951754

#SPJ1

3 0
2 years ago
136 is grater than 87
Luden [163]

Answer:

true

Step-by-step explanation:

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3 years ago
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(4x-9)(2x^2+2x+1) (4x−9)(2x 2 +2x+1)
tia_tia [17]

Answer:

(4x-9)^2*(2x^2+2x+1)^2

Step-by-step explanation:

(((4x-9)•(((2•(x2))+2x)+1))•(4x-9))•((2x2+2x)+1)

]  (((4x-9)•((2x2+2x)+1))•(4x-9))•(2x2+2x+1)

Trying to factor by splitting the middle term

Factoring  2x2+2x+1

The first term is,  2x2  its coefficient is  2 .

The middle term is,  +2x  its coefficient is  2 .

The last term, "the constant", is  +1

Step-1 : Multiply the coefficient of the first term by the constant   2 • 1 = 2

Step-2 : Find two factors of  2  whose sum equals the coefficient of the middle term, which is   2 .

     -2    +    -1    =    -3

     -1    +    -2    =    -3

     1    +    2    =    3

     2    +    1    =    3

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

 ((4x-9)•(2x2+2x+1)•(4x-9))•(2x2+2x+1)

Multiplying Exponential Expressions:

4.1    Multiply  (4x-9)  by  (4x-9)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (4x-9)  and the exponents are :

         1 , as  (4x-9)  is the same number as  (4x-9)1

and   1 , as  (4x-9)  is the same number as  (4x-9)1

The product is therefore,  (4x-9)(1+1) = (4x-9)2

Trying to factor by splitting the middle term

5.1     Factoring  2x2+2x+1

The first term is,  2x2  its coefficient is  2 .

The middle term is,  +2x  its coefficient is  2 .

The last term, "the constant", is  +1

Step-1 : Multiply the coefficient of the first term by the constant   2 • 1 = 2

Step-2 : Find two factors of  2  whose sum equals the coefficient of the middle term, which is   2 .

     -2    +    -1    =    -3

     -1    +    -2    =    -3

     1    +    2    =    3

     2    +    1    =    3

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Multiplying Exponential Expressions:

5.2    Multiply  (2x2+2x+1)  by  (2x2+2x+1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (2x2+2x+1)  and the exponents are :

      1 , as  (2x2+2x+1)  is the same number as  (2x2+2x+1)1

and   1 , as  (2x2+2x+1)  is the same number as  (2x2+2x+1)1

The product is therefore,  (2x2+2x+1)(1+1) = (2x2+2x+1)2

Final result :

 (4x - 9)2 • (2x2 + 2x + 1)2

6 0
2 years ago
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