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2 years ago

Prove that the circumcenter of a triangle is equidistant from its vertices.

Mathematics

1 answer:

ruslelena [56]2 years ago

5 0

Answer:

Step-by-step explanation:

The circumcenter is equidistant from the three vertices of the triangle. From the figure shown, we will prove DA = DB = DC. 2) DA = DB, DC = DB(If a point is on the perp. bisector of a segment, it is equidistant from each endpoint of the segment.)

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If you measure 5/6 meter how many twelfths have you measured

Alinara [238K]

1/6 = 2/12 because 12 is 2 times 6.
Multiply both numbers by 2 to get your answer:
5/6 = 10/12

4 0

2 years ago

3/8x - 1/4 =1/2<br><br> Please hurry

4vir4ik [10]

Answer:

x=2

Step-by-step explanation:

hope this helps :)

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2 years ago

∠G and ∠H are supplementary; m∠G = (x + 4)° and m∠H = (4x + 11)°. What is the measure of ∠G? What is the measure of ∠H?

iogann1982 [59]

Answer:

∠G = 37°

∠H = 143°

Step-by-step explanation:

As we know ,

Sum of supplementary angles is 180 degrees.

Hence sum of ∠G and ∠H is also 180 degrees

∠G + ∠H = 180

Substituting the given values in above equation, we get -

$(X+4) + (4X +11) = 180\\5X + 15 = 180\\5X = 165\\X = 33$

∠G = (x + 4)° = (33 + 4)° = 37°

∠H = (4x + 11)° = (33*4 + 11)° = 143°

3 0

2 years ago

Which TWO answers indicate why it's important to round numbers?

Anni [7]

<span>-Calculations may lead to long decimals, but money is in dollars and cents.
-Looks neater</span>

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2 years ago

Read 2 more answers

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konstantin123 [22]

Answer:

11.34x + 9.45y = 141.75

y = (141.75 - 11.34x)/9.45

y = -1.2x + 15

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(0,15)

(12.5,0)

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3 years ago