Question

find the y-cordinates of the points that are 10 units away from the point (7,6) that have a x-cordinate of -1

Answer 1

Answer:

y = {0 , 12}, x = -1

point 1     (-1, 0)

point 2    (-1, 12)

Step-by-step explanation:

use the distance formula

d² = (∆x)² + (∆y)²

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10 units away from the point (7,6)

x-cordinate of -1

10² = (-1 - 7)² + (y - 6)²

100 = 64 + (y - 6)²

Subtract 64 from both sides

36 = (y - 6)²

Take the square root of both sides

±6 = y - 6

Add 6 to both sides

y = {0 , 12}

point 1

(-1, 0)

point 2

(-1, 12)