Step-by-step explanation:
Let's represent the two integers with the variables 
and 
.
From the problem statement, we can create the following two equations:
With the first equation, we can subtract from both sides to isolate the variable to the left-hand side:
Now that we have a value for , we can plug it into the second equation and solve for :
Now, let's move everything to one side of the equation:
Factoring this quadratic will give us two values for :
Since we now know , we can plug this back into either of the original equations to get a value for , which will be 
.
So the two numbers that sum to 
and have a product of 
are 
.
Answer:
x ∈ {2π/3, π, 4π/3} ≈ {2.09440, 3.14159, 4.18879}
Step-by-step explanation:
The equation can be put into standard form by adding 1:
2cos²(x) +3cos(x) +1 = 0
(2cos(x) +1)(cos(x) +1) = 0
Values of cos(x) that make this true* are ...
cos(x) = -1/2 . . . . . . . . . true for x=2π/3, x=4π/3
cos(x) = -1 . . . . . . . . . . . true for x=π
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A graphing calculator can be helpful here, too.
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* from your knowledge of the short table of trig functions and their signs in different quadrants
586/10 -> 293/5 -> 58 3/5
