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Drupady [299]
3 years ago
12

Please help!!

Mathematics
1 answer:
Lelu [443]3 years ago
8 0
I answer for one shoves is 11pound and two is 22pound sorry if it is wrong
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The average wage for an electrician in CA is $25.47/hour. That is 11% above the national average. What is the national average?​
yan [13]

Answer:

$22.95/hour.

Step-by-step explanation:

It is given that the average wage for an electrician in CA is $25.47/hour. That is 11% above the national average.

Let as consider x be the national average.

11% above the national average is

x+\dfrac{11}{100}x=x+0.11x=1.11x

The average wage for an electrician in CA is 11% above the national average. So,

1.11x=25.47

Divide both sides by 1.11.

x=\dfrac{25.47}{1.11}

x=22.945945...

x=22.95

Therefore, the national average is $22.95/hour.

3 0
3 years ago
Help me with this plz
Paul [167]
1) 7000+300+10+3
2) 900,000+90,000+400+40+6
3) 600+80+2
4)30,000+7000+900+10+1
5)3,000,000+900,000+40,000+1,000+400+70+7
6)8000+400+70+4
7)700+70+2
8)30,000+7000+200+80+2
9)700,000+30,000+5,000+800+10+1
10)40,000+6000+400+40+9
11)5000+8000+70+2
12)5,000,000+700,000+50,000+8,000+900+40+5
13)5,000,000+900,000+90,000+8,000+800+90+0
14)300+70+7
15)300,000+20,000+3,000+200+40+8
5 0
3 years ago
Read 2 more answers
There are $1.95 worth of nickels and quarters in a piggy bank there are three more nickels than quarters how many of each are in
Gennadij [26K]

Answer:

6 quarters and 9 nickels

Step-by-step explanation:

6 quarters is equal to $1.50. 6 nickels is equal to $0.30. Those together equal $1.80, then add the three nickels bringing your total to $1.95.

3 0
3 years ago
Read 2 more answers
Look at attachment down below. If can’t see let me know
Vesnalui [34]

Answer:

C and E

Step-by-step explanation:

C and E are the correct answer

4 0
3 years ago
F(t)=t^2+19t+60<br> What are the zeros of the function and what is the vertex of the parabola?
SVEN [57.7K]

Answer: -4,-15;\ \left(-\dfrac{19}{2},-\dfrac{121}{4}\right)

Step-by-step explanation:

Given

Function is F(t)=t^2+19+60

Zeroes of the function are

t^2+19t+60=0\\\\\Rightarrow t=\dfrac{-19\pm\sqrt{19^2-4\times 1\times 60}}{2\times 1}\\\\\Rightarrow t=\dfrac{-19\pm \sqrt{121}}{2}\\\\\Rightarrow t=\dfrac{-19\pm 11}{2}\\\\\Rightarrow t=-4,-15

Using completing the square method

y=t^2+2\times \dfrac{19}{2}t+\dfrac{19^2}{2^2}-\dfrac{19^2}{2^2}+60\\\\y=\left(t+\dfrac{19}{2}\right)^2+60-\dfrac{361}{4}\\\\y=\left(t+\dfrac{19}{2}\right)^2-\dfrac{121}{4}\\\\y+\dfrac{121}{4}=\left(t+\dfrac{19}{2}\right)^2\\\\\left(y-(-\dfrac{121}{4}\right)=\left(t-(-\dfrac{19}{2})\right)^2\\\\\text{The vertex is }\left(-\dfrac{19}{2},-\dfrac{121}{4}\right)

4 0
3 years ago
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