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2 years ago

14

What is the length of each side ? help please

1 answer:

Margarita [4]2 years ago

6 0

Lengths are 11cm , 13cm , 16cm , 12cm

Step-by-step explanation:

Perimeter = Sum of measure of all the sides of quadrilateral.

In the question , perimeter = 52 cm

So,

$x + (x + 2) + 2(x - 3) + (x + 1) = 52$

$= > x + x + 2 + 2x - 6 + x + 1 = 52$

$= > 5x - 3 = 52$

$= > 5x = 52 + 3 = 55$

$= > x = \frac{55}{5} = 11$

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2 years ago

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Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

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2 years ago

Erika pours 6 cups of milk into 8 glasses. Each glass has the same amount of milk. How many cups of milk are in each glass?

MrMuchimi

Answer:

each glass will have 0.75 of a cup or 3/4 of a cup * 0.75 and 3/4 is the same*

7 0

2 years ago

Someone help me please!!!

mezya [45]

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8 0

2 years ago

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I don’t understand this

Oxana [17]

You have to multiply whats outside the parenthesis with everything that is inside, so

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$x^{-3}y^0.x^2-x^{-3}y^0.3x^5y^4$

Multiplication of same bases we sum the exponents

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$x^{-1}.1-3x^2y^4$

$x^{-1}-3x^2y^4$

Alternative B.

7 0

2 years ago