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3 years ago

Section 25 Exercise's

Mathematics

1 answer:

erastovalidia [21]3 years ago

6 0

Djejshshshajkshwbshsnajajahahahanananan

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What is the product of − 3/11 and − 2/15? please explain.

emmainna [20.7K]

ANSWER

The product is

$\frac{2}{55}$

EXPLANATION

To find the product of

$- \frac{3}{11}$

and

$\frac{ - 2}{15}$

means we should multiply the two fractions.

We multiply to obtain,

$- \frac{3}{11} \times - \frac{2}{15}$

$= - \frac{3}{11} \times - \frac{2}{3 \times 5}$

Cancel the common factors:

$= - \frac{1}{11} \times - \frac{2}{5}$

Now, multiply the numerators separately and the denominators too separately.

$= \frac{ - 1 \times - 2}{11 \times 5}$

This simplifies to,

$= \frac{2}{55}$

4 0

3 years ago

If f(x)= 4-2x and g(x)=6x which expression is equivalent to (g-f)(3)

Dmitrij [34]

Answer:

(g-f)(3) = 20

Step-by-step explanation:

g(3)=6 * (3) = 18

f(3)= 4-2(3) = 4 - 6 = -2

(g-f)(3) = 18 - (-2) = 20

4 0

3 years ago

A car has mass 1500 kg and is traveling at a speed of 35 miles/hour. what is its kinetic energy in joules? (Be sure to convert m

photoshop1234 [79]

Answer:

Factor by which kinetic energy increase = 4 times

Step-by-step explanation:

Given,

Mass of the car, v1 = 1500 kg

initial speed of car = 35 miles/h

$=\dfrac{35\times 1609.34}{3600}\ m/s$

= 15.64 m/s

Initial kinetic energy of the car is given by,

$k_1\ =\ \dfrac{1}{2}.m.v_1^2$

$=\ \dfrac{1}{2}\times 1500\times (15.64)^2\ joule$

= 183606.46 J

Final velocity of car v2 = 70 miles/hour

$=\dfrac{70\times 1609.34}{3600}$

= 31.29 m/s

So, final kinetic energy of car is given by

$k_2\ =\ \dfrac{1}{2}.m.v_2^2$

$=\ \dfrac{1}{2}\times 1500\times (31.29)^2$

= 734425.84 J

Now, the ratio of final to initial kinetic energy can be given by,

$\dfrac{k_2}{k_1}=\ \dfrac{734425.84}{183606.46}$

$=>\ k_2\ =\ 4k_1$

Hence, the kinetic energy will increase by 4 times.

7 0

3 years ago

What is the length of segment AD.

slamgirl [31]

Answer:

AD= 5.82 units (3 s.f.)

Step-by-step explanation:

Please see attached picture for full solution.

*skipped these steps in the beginning:

∠ABC +∠ABD= 180° (adj. ∠s on a str. line)

90° +∠ABD= 180°

7 0

3 years ago

What is 209 rounded to the nearest ten and hundred

Ad libitum [116K]

209 rounded to the nearest ten; 210

209 rounded to the nearest hundred; 200

Hope this helped ;)

3 0

3 years ago

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