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monitta
3 years ago
6

Will someone plz do this question​

Mathematics
1 answer:
Illusion [34]3 years ago
6 0

Answer:

the answer is a your welcome

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I need help on this please
Dahasolnce [82]

Answer:

B

x \geqslant  - 0.9

6 0
2 years ago
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Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re
fiasKO [112]

Answer: R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts 38^{\circ} angle to each other

The resultant of the two forces is given by

\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}

Insert the values

\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb

Resultant makes an angle of

\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}

So, the resultant makes an angle of 22.57^{\circ} with 9 lb force

Angle made with 13 lb force is 38^{\circ}-22.57^{\circ}=15.43^{\circ}

7 0
3 years ago
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Pls help meee<br>thank you thank you thank you thank you
olga_2 [115]

Answer:

See below

Step-by-step explanation:

11 box 1: 12

11 box 2: 101

12 box 1: 80

12 box 2: 80

12 box 3: 80

13 box 1: 16

13 box 2: 16

13 box 3: 76


20 = y + 12

20 - 12 = y + 12 - 12

8 = y


x + 2 = 19

x + 2 - 2 = 19 - 2

x = 17


z - 313 = 176

z - 313 + 313 = 176 + 313

z = 489

6 0
3 years ago
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Use the tens frame to help you solve the problem below 8+4×10
ipn [44]
Instead i use pemdas so the answer to this problem would be 48 
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3 years ago
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PLEASE HELP!!
Alborosie

Answer:

A

Step-by-step explanation:

7 0
3 years ago
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