The given equation is a Quadratic equation, so it's graph must be a parabola, and the Coefficient of x² is positive that means the parabola must have an opening upward.
And 2 is added to the ideal equation, so the parabola must have shift 2 units up from x - axis.
From the above information, we can easily conclude that the Correct representation is done in graph 4
This exercise is about a proof in Euclidian geometry. See the explanation below.
<h3>What is Euclidian Geometry?</h3>The study of solid and flat objects using the axioms and theorems developed by the Greek mathematician Euclid is known as Euclidean geometry (c. 300 bce).
<h3>What is the statement that completes the above proof?</h3>Given that S is the midpoint of :
Hence QS = TS ......................1
It is right to indicate that
PQ = TV ........................2
And ∠RSQ is vertically opposite to ∠TSV
Hence
∠RSQ = ∠TSV.........................3
Given 1, 2, and 3,
Δ QRS ≅ ΔVTS
Therefore,
Δ QRS ≅ ΔVTS
and ∠ RSQ can be termed to be congruent to ∠TSV.
<h3>What does it mean for an angel to be congruent?</h3>It is to be noted that the measure of an angle is the same for congruent angles. An ordinary pentagon, for instance, has five sides and five angles, each of which is 108 degrees.
The angles of a regular polygon will always be congruent, regardless of its size or scale.
Learn more about Euclidean Proof:
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