Question

A tennis ball is hit with an initial velocity of 15 m/s at an angle of

Answer 1

Answer:

Horizontal acceleration is 0 in a projectile motion

Explanation:

first we have to find the horizontal velocity

15cos40 = 11.49ms^-1

and then use the following equation to find the distance

$s = ut + \frac{1}{2} a {t}^{2} \\ s = 11.49 \times 2 \\s = 22.98m$