The decay function is of the form
where
N₀ = initial amount
k = decay constant
t = hours
The material decays by 10% in 95 hours. Therefore
The time for the half life is given by
Answer: The half life is 625 hours
To solve this problem it is necessary to apply the concepts related to pressure as a unit that measures the force applied in a specific area as well as pressure as a measurement of the density of the liquid to which it is subjected, its depth and the respective gravity.
The two definitions of pressure can be enclosed under the following equations
Where
F= Force
A = Area
Where,
Density
g = Gravity
h = Height
Our values are given as,
If we make a comparison between the lid and the tube, the diameter of the tube becomes negligible.
Matching the two previous expressions we have to
Re-arrange to find h
Therefore the height of water in the tube is 7.9cm
Answer:
Temperature of parcel at 1000 ft is 85.5°F
Explanation:
Temperature of parcel at 0 ft =T₁ = 91.0°F
Dry adiabatic rate = 5.5°F/100 ft
Temperature of parcel at H₂ (1000 ft) = T₂ =?
Height of LCL = 5000 ft
As (1000<5000), so using the formula for parcel below or at the LCL i.e.
Answer:
The volume would be 364 L
Explanation:
This is an ideal gases problem and the specific situation is expansion. To find the final volume, we must study two states:
Initial
Final
Then, we use the equation of ideal gases and as temperature is constant, we can solve it as follows:
As you see, the final volume is greater than the initial, because the pressure drops and pressure and volume are inversely proportional.
Answer:
a) 0 V
b) 10 turns
c) 4000 turns
d) 12.5 A
e) 400 W
f) 0.5 A
g) 95.4%
Explanation:
A
0
B
To solve this, we would be using the simple relationship between voltage and number of turns
V1/V2 = N1/N2
500/25 = 200/N2
20 = 200/N2
N2 = 200/20
N2 = 10 turns
C
Here also, we would be using the relationship between current and the number of turns
I1/I2 = N2/N1
500/25 = N2/20
20 = N2/20
N2 = 20 * 20
N2 = 4000 turns
D
Like in the previous question, current and the number of turn relationship is used
N1/N2 = I2/I1
400/80 = I2/2.5
5 = I2/2.5
I2 = 5 * 2.5
I2 = 12.5 A
E
The power remains unchanged at 400 W
F
Power = Voltage * Current
P = VI
I = P/V
I = 60/120
I = 0.5 A
G
95.4%