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g100num [7]
3 years ago
10

3

Physics
1 answer:
bezimeni [28]3 years ago
6 0

Answer:

<h2>31km/h</h2>

Explanation:

Step one:

given data

speed of bus= 35km/h forward

speed of ball= 4km/h backwards

`Step two:

Required

the magnitude of the velocity of the ball relative to the ground is the net velocity

that is

=35-4

=31km/h

<em><u>The velocity of the ball relative to the ground is 31km/h</u></em>

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3 0
4 years ago
Suppose that a ball is released from the window of a train that is moving with constant velocity.  The path of the ball, as obse
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7 0
3 years ago
Three small masses are positioned as follows: 2.0 kg at (0.0 m, 0.0 m), 2.0 kg at (2.0 m, 0.0 m), and 4.0 kg at (2.0 m, 1.0 m).
melamori03 [73]
Refer to the diagram shown below.

The given data is

mass, kg   Coordinates. m
-------------   -----------------
   2               (0, 0)
   2               (2, 0)
   4               (2, 1)

Total mass, M = 2+2+4 = 8kg
Let (x,y) be the coordinates of M.

Then, taking moments about the origin, we obtain
8x = 2*0 + 2*2 + 4*2 = 12
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8y = 2*0 + 2*0 + 4*1 = 4
y = 0.5 m

Answer:  (1.5, 0.5) m




6 0
3 years ago
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