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charle [14.2K]
3 years ago
9

21. For this table of data, how should the y-axis be labeled (with units)?

Physics
1 answer:
Snowcat [4.5K]3 years ago
8 0

Answer:

The y-axis would be labeled with displacement (m)

Explanation:

The displacement is dependent on the force applied.

Labels should have what you measure and how your units of measure.

The x-axis would be labeleed with force applied (N)

The y-axis would be labeled with displacement (m)

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What will cause the volume of an ideal gas to triple in value?
trapecia [35]

Answer: The volume of an ideal gas will triple in value if the pressure is reduced to one-third of its initial value

Explanation:

We can determine this from the gas laws. Using Boyle's law, which states that "the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature"

Mathematically, P ∝ (1/V)

Since P ∝ (1/V), we can then write that

P = k(1/V)

Where P is the pressure, V is the volume and k is the proportionality constant

PV = k

We can then write that

P1V1 = P2V2 = P3V3 = ...

Hence, P1V1 = P2V2

Where P1 is the initial pressure of the gas

P2 is the final pressure of the gas

V1 is the initial volume of the gas

and V2 is the final volume of the gas

From the question, we want to determine what will make the new volume be thrice the initial volume.

Hence,

P1 = P

V1 = V

P2= ??

V2 = 3V

Therefore,

P × V = P2 × (3V)

P2 = PV/3V

P2 = P/3 = 1/3(P)

This means the volume of an ideal gas will triple in value if the pressure is reduced to one-third of its initial value

6 0
3 years ago
Read 2 more answers
1. What is the temperature in Kelvin and Fahrenheit of silver at 51.4oC?1. What is the temperature in Kelvin and Fahrenheit of s
horsena [70]

Answer:

Temperature in Fahrenheit will be 124.52°F and in kelvin 324.4 K

Explanation:

We have given temperature in of silver in degree Celsius as 51.4^{\circ}C

We have to convert this temperature in Fahrenheit and kelvin

For Fahrenheit

Temperature in Fahrenheit   = \frac{9}{5}\times 51.4+32=124.52^{\circ}F

For kelvin

In kelvin = 51.4+273 = 324.4 K

So temperature in Fahrenheit will be 124.52°F and in kelvin 324.4 K

5 0
3 years ago
How can the shapes of a boat and an airplane affect how water and wind forces act on the objects?
gulaghasi [49]
It would be Aerodinmic 
5 0
4 years ago
The free-electron density in a copper wire is 8.5×1028 electrons/m3. The electric field in the wire is 0.0520 N/C and the temper
meriva

Answer:

(a) 1.87 x 10⁻⁴ m/s

(b) 0.013V

Explanation:

(a) Drift speed, v_{d} , is the average velocity that a charged particle can have due to an electric field. For a given current, I, the drift velocity is given by;

v_{d} = \frac{I}{qnA}             ----------------(i)

Where;

q = amount of charge

n = free charge density

A = cross-sectional area of the wire

But current density, J, is the electric current per unit cross-section area. This  is also equal to the ratio of the electric field, E, to the resistivity, p, of the material of the wire. i.e

J = \frac{I}{A} = \frac{E}{p}

Equation (i) can then be written as follows;

v_{d} = \frac{J}{qn} = \frac{E}{qnp}

v_{d} = \frac{E}{qnp}      ---------------------(ii)

From the question;

E = 0.0520N/C

p = 1.72 x 10⁻⁸ Ωm

n = 8.5 x 10²⁸ electrons/m³

c = charge on electron = 1.9 x 10⁻¹⁹C

Substitute these values into equation (ii) as follows;

v_{d} = \frac{0.0520}{1.9*10^{-19} * 8.5*10^{28} * 1.72*10^{-8}}

v_{d} = 1.87 x 10⁻⁴ m/s

(b) The potential difference, V, is given by the product of the electric field and the distance, d, between the two points in the wire. i.e

V = E x d        [where d = 25.0cm = 0.25m]

V = 0.0520 x 0.25

V = 0.013V

4 0
3 years ago
As a train enters the station it slows down from 40 m/s to a 10 m/s in 5 seconds
lora16 [44]

Answer:

See the answers below.

Explanation:

To solve this problem we must use the following equation of kinematics.

v_{f}=v_{o}-a*t

where:

Vf = final velocity = 10 [m/s]

Vo = initial velocity = 40 [m/s]

t = time = 5 [s]

a = acceleration [m/s²]

Now replacing:

10=40-a*5\\40-10=a*5\\30=5*a\\a=6[m/s^{2}]

Note: The negative sign in the above equation means that the velecity is decreasing.

2)

To solve this second part we must use the following equation of kinematics.

v_{f}^{2} =v_{o}^{2} -2*a*x\\

where:

x = distance [m]

(10)^{2} =(40)^{2} -2*6*x\\100=1600-12*x\\12*x=1600-100\\12*x=1500\\x=125[m]

7 0
3 years ago
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