<span>c) what is the angle (relative to the horizontal) of the balls initial velocity?
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Answer:
Explanation:
Mass of ball Is m=96.1g=0.0961kg
Height above spring is 59.1cm
L=0.591m
Extension of the spring is 4.75403cm
e=0.0475403m
Then the distance the ball traveled is H=L+e
H=0.591+0.0475403
H=0.6385403m
Then, the potential energy of the ball is given as
P.E=mgh
P.E=0.0961×9.81×0.6385403
P.E=0.602J
From conservation of energy, energy cannot be created nor destroy but can be transferred from one form to another
Then, the P.E is transferred to the work done by the spring
Then, Work done by spring is given as
W=½ke²
W=P.E=½×k×0.0475403²
0.602=½×k×0.0475403²
k=0.602×2/0.0475403²
k=532.72N/m
The spring constant is 532.72 N/m
Therefore, the volume of the gas at temperature 100°C is 4.62L
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<u>Explanation:</u>
Given-
Volume, V1 = 4L
Temperature, T1 = 50°C = 50 + 273K = 323K
Temperature, T2 = 100°C = 100 + 273K = 373K
Volume, V2 = ?
Using Charles law:
V1/T1 = V2/T2
4/323 = V2/373
V2 = 4.62L
Therefore, the volume of the gas at temperature 100°C is 4.62L
Answer:
Explanation:
ASSUMING the 52° is the angle of incidence measured from the perpendicular to the surface
n₁sinθ₁ = n₂sinθ₂
1 sin52 = 1.33sinθ₂
θ₂ = arcsin(sin52 / 1.33)
θ₂ = 36°
as measured from the perpendicular to the surface