You multiply 3/16 by 3 and you should get 9/48
Answer:

Step-by-step explanation:
the general equation of a circle is

with (h,k) being the centre of the circle and r the radius
Let h = height of the box,
x = side length of the base.
Volume of the box is

.
So

Surface area of a box is S = 2(Width • Length + Length • Height + Height • Width).
So surface area of the box is


The surface are is supposed to be the minimum. So we'll need to find the first derivative of the surface area function and set it to zero.

![4x = \frac{460}{ x^{2} } \\ 4x^{3} = 460 \\ x^{3} = 115 \\ x = \sqrt[3]{115} = 4.86](https://tex.z-dn.net/?f=%204x%20%3D%20%5Cfrac%7B460%7D%7B%20x%5E%7B2%7D%20%7D%20%20%5C%5C%20%204x%5E%7B3%7D%20%3D%20460%20%20%5C%5C%20x%5E%7B3%7D%20%3D%20115%20%20%5C%5C%20x%20%3D%20%20%5Csqrt%5B3%5D%7B115%7D%20%3D%204.86%20)
Then

So the box is 4.86 in. wide and 4.87 in. high.
0.000023 i hope that helps
Answer:
43.75feet
Step-by-step explanation:
Given the height of the tennis ball expressed as;
h(t) = -15t^2 + 45t + 10
At maximum height, the velocity of the ball is zero
v = dh/dt
dh/dt = -30t + 45
Since dh/dt = 0, hence;
0 = -30t + 45
30t = 45
t = 45/30
t = 3/2
t = 1.5secs
Substitute t = 1.5 into the expression given
h(1.5) = -15(1.5)^2 + 45(1.5) + 10
h(1.5) = -15(2.25)+67.5+10
h(1.5) = -33.75+77.5
h(1.5) = 43.75feet
Hence the maximum height of the ball is 43.75feet