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2 years ago

All of the stars in the sky, except for one, are so far away that they look like small points of light.

Chemistry

1 answer:

kiruha [24]2 years ago

8 0

Answer:

The sun.

Explanation:

It is closer to Earth, therefore bigger to us, and not just a small point of light.

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A scientist has a new cough medicine by giving it to a group of course the scientist gives another group called the liquid and t

Liula [17]

Answer:50

Explanation:

Just look it up

6 0

3 years ago

From what are chemical sedimentary rocks formed?

masha68 [24]

Chemicals dissolved in water. Calcite is a good example, if I'm not mistaken.

6 0

3 years ago

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Identify the type of bonding within each substance. Co ( s ) ionic covalent metallic CoCl 2 ( s ) covalent ionic metallic CCl 4

krok68 [10]

Answer:

1. Co ( s ) - metallic bonding

2. CoCl₂ ( s ) - ionic bonding

3. CCl₄ ( l ) - covalent bonding

Explanation:

Metallic bonding -

It is the type of bonding present between the atoms of the metals , via the electrostatic interaction between the metal and the delocalized electrons , is known as metallic bonding .

For example ,

Mostly metals show metallic bonding .

Ionic bonding -

It is the type of bonding present between the ions i.e. , the cation and the anion is known as ionic bonding .

For example ,

Mostly ionic compound , like salts show ionic bonding .

Covalent bonding -

It is the type of bonding which is present between shared pair of electrons , is known as covalent bonding .

For example ,

Most of the carbon compounds are capable to show covalent bonding .

Hence , from the question ,

1. Co ( s ) - metallic bonding

2. CoCl₂ ( s ) - ionic bonding

3. CCl₄ ( l ) - covalent bonding

6 0

3 years ago

A 0.271g sample of an unknown vapor occupies 294ml at 140C and 874mmHg. The emperical formula of the compound is CH2. How many m

Phoenix [80]

Using PV = nRT, we can calculate the moles of the sample.
874 mmHg = 116,524 Pa
n = PV/RT
n = 116,524 x 294 x 10⁻⁶ / 8.314 x (140 + 273)
n = 9.98 x 10⁻³ mol

moles = mass / Mr
Mr = 0.271/9.98 x 10⁻³
Mr = 27.2
Mass of empirical formula = 14
Repeat units = 27.2 / 14 ≈ 2

Formula of substance:
C₂H₄

Combustion equation:
C₂H₄ + 3O₂ → 2CO₂ + 2H₂O

1 mole produces 2 moles of CO₂, so 3 moles will produce 6 moles CO₂

7 0

2 years ago

How is an oxidation half-reaction written using the reduction potential chart? How is the oxidation potential voltage determined

insens350 [35]

Oxidation half reaction is written as follows when using using reduction potential chart
example when using copper it is written as follows
CU2+ +2e- --> c(s) +0.34v
oxidasation is the loos of electron hence copper oxidation potential is as follows
cu (s) --> CU2+ +2e -0.34v

7 0

3 years ago

Read 2 more answers