B,speedof light>speed of sound
To calculate this, the first step is to determine the number of protons in each atom of the ion. You can use their atomic number to find the number of protons. If the number protons and electrons are equal there is no charge, so the next step is to determine how many electrons to add or remove to the number of protons.
B. Endorphins are released during exercise
<u>Answer:</u> The rate law expression is
and value of 'k' is 
<u>Explanation:</u>
Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
For the given chemical equation:

Rate law expression for the reaction:
![\text{Rate}=k[NO]^a[O_2]^b](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BNO%5D%5Ea%5BO_2%5D%5Eb)
where,
a = order with respect to nitrogen monoxide
b = order with respect to oxygen
- <u>Expression for rate law for first observation:</u>
....(1)
- <u>Expression for rate law for second observation:</u>
....(2)
- <u>Expression for rate law for third observation:</u>
....(3)
Dividing 1 from 2, we get:

Dividing 1 from 3, we get:

Thus, the rate law becomes:
![\text{Rate}=k[NO]^2[O_2]^1](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BNO%5D%5E2%5BO_2%5D%5E1)
Now, calculating the value of 'k' by using any expression.
Putting values in equation 1, we get:
![8.55\times 10^{-3}=k[0.030]^2[0.0055]^1\\\\k=1.727\times 10^3M^{-2}s^{-1}](https://tex.z-dn.net/?f=8.55%5Ctimes%2010%5E%7B-3%7D%3Dk%5B0.030%5D%5E2%5B0.0055%5D%5E1%5C%5C%5C%5Ck%3D1.727%5Ctimes%2010%5E3M%5E%7B-2%7Ds%5E%7B-1%7D)
Hence, the rate law expression is
and value of 'k' is 
C,H and O are present in monosaccharides