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3 years ago

The answer is 315 . I a a student but i am smart i promise its the answer

Mathematics

2 answers:

8_murik_8 [283]3 years ago

3 0

Answer:

umm.. ok?

Step-by-step explanation:

Stolb23 [73]3 years ago

3 0

There is no question here.

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Rewrite the product as a sum: 10cos(5x)sin(10x)

mote1985 [20]

Answer:

10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]

Step-by-step explanation:

In this question, we are tasked with writing the product as a sum.

To do this, we shall be using the sum to product formula below;

cosαsinβ = 1/2[ sin(α + β) - sin(α - β)]

From the question, we can say α= 5x and β= 10x

Plugging these values into the equation, we have

10cos(5x)sin(10x) = (10) × 1/2[sin (5x + 10x) - sin(5x - 10x)]

= 5[sin (15x) - sin (-5x)]

We apply odd identity i.e sin(-x) = -sinx

Thus applying same to sin(-5x)

sin(-5x) = -sin(5x)

Thus;

5[sin (15x) - sin (-5x)] = 5[sin (15x) -(-sin(5x))]

= 5[sin (15x) + sin (5x)]

Hence, 10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]

8 0

3 years ago

Simplify 4.2^-3 x 5.1^2 x 4.2^4 x 5.1^3

Stolb23 [73]

Answer:

14491.060542

Step-by-step explanation:

5 0

3 years ago

Round off 9.999 to the nearest 10

dlinn [17]

Answer:

the answer is 10 you round up a nine it keeps going to the end

6 0

3 years ago

A college conducts a common test for all the students. For the Mathematics portion of this test, the scores are normally distrib

Jet001 [13]

Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 502, \sigma = 115$

The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:

X = 590:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{590 - 502}{115}$

Z = 0.76

Z = 0.76 has a p-value of 0.7764.

X = 400:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{400 - 502}{115}$

Z = -0.89

Z = -0.89 has a p-value of 0.1867.

0.7764 - 0.1867 = 0.5897 = 58.97%.

58.97% of students would be expected to score between 400 and 590.

More can be learned about the normal distribution at brainly.com/question/27643290

#SPJ1

6 0

2 years ago

I will mark you brainiest if you can answer this

Korvikt [17]

Answer:

12^4 or 20736

Step by Step Instructions:

really all you have to do is subtract the exponents. 12^7-12^3=12^4, if you want to expand the numbers you can do it that way too. 12^7=35831808, 12^3=1728, 35831808/1728=20736 (which is the same as 12^4)

4 0

3 years ago