Sum of 2 perfect cubes
a³+b³=(a+b)(x²-xy+y²)
so
x³+4³=(x+4)(x²-4x+16)
set each to zero
x+4=0
x=-4
the other one can't be solveed using conventional means
use quadratic formula
for
ax^2+bx+c=0
x=

for x²-4x+16=0
x=

x=

x=

x=

x=

x=

the roots are
x=-4 and 2+2i√3 and 2-2i√3
Answer:
Step-by-step explanation:
2x = 2*x
4y = 2*2*y
Common term = 2
2x + 4y = 2*x + 2*2y
=2*(x + 2y)
Answer:
12
Step-by-step explanation:
Answer:
a = 3
Step-by-step explanation:
1) Simplify 5a - 9 + a to 6a - 9.

2) Add 9 to both sides.

3) Simplify 9 + 9 to 18.

4) Divide both sides by 6.

5) Simplify 18/6 to 3.

Therefor, the answer is, a = 3.
Answer:
A
Step-by-step explanation:
This is the answer because the others don't make sense to me at all...
<em>PLEASE</em><em> </em><em>DO</em><em> </em><em>MARK ME</em><em> </em><em>AS BRAINLIEST</em><em> </em><em>UWU</em><em> </em>